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faltersainse [42]
3 years ago
12

3(x 2) 11 is greater than 20

Mathematics
1 answer:
Allushta [10]3 years ago
4 0
3(x+2)+11>20
minus 11 both sides
3(x+2)>9
divide both sides by 3
x+2>3
minus 2 both sides
x>1
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Yep! 
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Weighing #2: Now you have 6 coins left. Split the pile evenly again, 3 in each pile. Repeat the same process and put each pile on one side of the balance. The side that is weighed down has your fake coin in it. Ignore the other 3 coins.

Weighing #3: You have 3 coins left. Take two coins, whichever two you like, and weigh them. If they weigh the same, then the one you didn't weigh is the fake one. If one is heavier, then that heavier one is your fake coin.
5 0
3 years ago
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HELP HOW DO YOU WORK THIS OUT!!
Harrizon [31]

Answer:

I believe it would be 4/6

Step-by-step explanation:

You have four different ways to get a sum of 7: 1 and 6; 2 and 5; 3 and 4; or 4 and 3.

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3 years ago
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Step-by-step explanation:

i hope this helped

6 0
2 years ago
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6 0
3 years ago
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