Dimensions are length 20 meter and width 14 meter
<em><u>Solution:</u></em>
Let "a" be the length of rectangle
Let "b" be the width of rectangle
Given that,
<em><u>A rectangle has width that is 6 meters less than the length</u></em>
Width = length - 6
b = a - 6
The area of the rectangle is 280 square meters
<em><u>The area of the rectangle is given by formula:</u></em>

<em><u>Substituting the values we get,</u></em>

<em><u>Solve the above equation by quadratic formula</u></em>



Since, length cannot be negative, ignore a = -14
<em><u>Thus solution of length is a = 20</u></em>
Therefore,
width = length - 6
width = 20 - 6 = 14
Thus dimensions are length 20 meter and width 14 meter
Answer:
V = 150.72 cm³.
Step-by-step explanation:
First, get the volume of a cylinder.
V = πr²h
Where:
π = 3.14 (given)
r = radius (half of diameter, or 2)
h = height (12)
Knowing this, substitute the known values.
V = πr²h
V = (3.14)(2²)(12)
Square 2.
V = (3.14)(4)(12)
Multiply 3.14 and 4.
V = (12.56)(12)
Multiply 12.56 and 12.
V = 150.72.
Since it is already rounded to the nearest hundredth, that is your answer.
Answer:
Step-by-step explanation:
0.9*2b = 1.8b
0.9*-1 = -0.9
So far we have 1.8b-0.9. It can't be simplified further.
Then, we add the 2nd part, -0.5b+1.
We have:
1.8b-0.9-0.5b+1. Next we combine like terms.
1.8b-0.5b = 1.3b.
-0.9+1 = 0.1
Then we put it together.
1.3b+0.1 is our answer.
Hope this helped! Have a nice day :D
The estimate is twelve because five goes into sixty roughly twelve times.
Answer:
Step-by-step explanation:
Given is a Laplace transform of f(t) as

Let

Solving we get 

Solving B=0=D

Hence we have
f(t) = inverse Laplace of
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