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Arturiano [62]
3 years ago
8

There are 4 boys and 2 girls from the 7th grade and 3 boys and 5 girls from the 8th grade on the soccer team. The coach will pic

k one captain from each grade. What is the probability that he will pick a boy from the 7th grade and a girl from the 8th grade?
Mathematics
1 answer:
kaheart [24]3 years ago
5 0

Answer:

5/12

Step-by-step explanation:

P(b,7) = 4/6

P(g,8) = 5/8

4/6 x 5/8 = 20/48 (or 5/12 reduced)

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5 m<br> 12 m<br> What is the length of the hypotenuse?<br> m
Gelneren [198K]

Answer:

the length is 40m

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. ​(a) Descri
OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

\mu = 74

and

\sigma = 6

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

\mu = 74

The standard error of the means becomes the standard deviation of the sampling distribution.

\sigma_ { \bar X }  =  \frac{ \sigma}{ \sqrt{n} }  \\ \sigma_ { \bar X }  =  \frac{ 6}{ \sqrt{36} }  = 1

Part b) We want to find

P(\bar X \:>\:75.9)

We need to convert to z-score.

P(\bar X \:>\:75.9)  = P(z \:>\: \frac{75.9 - 74}{1} )  \\  = P(z \:>\: \frac{75.9 - 74}{1} ) \\  = P(z \:>\: 1.9) \\  = 0.0287

Part c)

We want to find

P(\bar X \: < \:71.95)

We convert to z-score and use the normal distribution table to find the corresponding area.

P(\bar X \: < \:71.95)  = P(z \: < \: \frac{71.9 5- 74}{1} )  \\  = P(z \: < \: \frac{71.9 5- 74}{1} ) \\  = P(z \: < \:  - 2.05) \\  = 0.0202

Part d)

We want to find :

P(73\:

We convert to z-scores and again use the standard normal distribution table.

P( \frac{73 - 74}{1} \:< \: z

5 0
3 years ago
A simple random sample of size nequals15 is drawn from a population that is normally distributed. The sample mean is found to be
Bond [772]

Answer with explanation:

To test the Significance of the population which is Normally Distributed we will use the following Formula Called Z test

   z=\frac{\Bar X - \mu}{\frac{\sigma}{n}}

\Bar X =31.1\\\\ \sigma=6.3\\\\ \mu=25\\\\n=15\\\\z=\frac{31.1-25}{\frac{6.3}{\sqrt{15}}}\\\\z=\frac{6.1\times\sqrt{15}}{6.3}\\\\z=\frac{6.1 \times 3.88}{6.3}\\\\z=3.756

→p(Probability) Value when ,z=3.756 is equal to= 0.99992=0.9999

⇒Significance Level (α)=0.01

We will do Hypothesis testing to check whether population mean is different from 25 at the alpha equals 0.01 level of significance.

→0.9999 > 0.01

→p value > α

With a z value of 3.75, it is only 3.75% chance that ,mean will be different from 25.

So,we conclude that results are not significant.So,at 0.01 level of significance population mean will not be different from 25.

3 0
3 years ago
There are 6 marbles in a bag: 1 blue, 1 red, 1 white, 1 yellow, 1 green, and 1 black. Mary picks one marble at random and then h
stellarik [79]

Answer:

1 in 30

Step-by-step explanation:

1 in 6 chance Mary picks the red marble in the first place. After this there is a 1 in 5 chance her sister picks the blue one. 5 multiplied by 6 is 30.

7 0
2 years ago
Read 2 more answers
What is the product of the two binomials below (3A+4B)(3A-4B)
Mariulka [41]

Answer:

9A^2 - 16B^2.

Step-by-step explanation:

(3A+4B)(3A-4B) = 9A^2 + 12AB - 12AB - 16B^2 = 9A^2 - 16B^2.

Hope this helps!

5 0
3 years ago
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