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Zarrin [17]
3 years ago
14

Pls help

Physics
1 answer:
11111nata11111 [884]3 years ago
3 0

Answer:

what do u need help in?

Explanation:

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When light passes through a convex lens, it does this.....
Tpy6a [65]

Explanation:

6. Converge or come together

7. convex

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3 years ago
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Write the nuclear reaction equation for the beta decay of Iodine-131
den301095 [7]

Answer:

_{53}^{131}I \rightarrow _{54}^{131}Xe + e + \bar{\nu}

Explanation:

In a beta (minus) decay, a neutron in a nucleus turns into a proton, emitting a fast-moving electron (called beta particle) alongside with an antineutrino.

The general equation for a beta decay is:

^A_Z X \rightarrow _{Z+1}^AY+^0_{-1}e+ ^0_0\bar{\nu} (1)

where

X is the original nucleus

Y is the daughter nucleus

e is the electron

\bar{\nu} is the antineutrino

We observe that:

  • The mass number (A), which is the sum of protons and neutrons in the nucleus, remains the same in the decay
  • The atomic number (Z), which is the number of protons in the nucleus, increases by 1 unit

In this problem, the original nucles that we are considering is iodine-131, which is

_{53}^{131}I

where

Z = 53 (atomic number of iodine)

A = 131 (mass number)

Using the rule for the general equation (1), the dauther nucleus must have same mass number (131) and atomic number increased by 1 (54, which corresponds to Xenon, Xe), therefore the equation will be:

_{53}^{131}I \rightarrow _{54}^{131}Xe + e + \bar{\nu}

7 0
3 years ago
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A 0.58 kg mass is moving horizontally with a speed of 6.0 m/s when it strikes a vertical wall. The mass rebounds with a speed of
Sunny_sXe [5.5K]

Answer:

5.8\; {\rm kg\cdot m \cdot s^{-1}}.

Explanation:

If the mass of an object is m and the velocity of that object is v, the linear momentum of that object would be m\, v.

Assume that the initial velocity of the mass is positive (6.0\; {\rm m\cdot s^{-1}}.) However, the direction of the velocity is reversed after the impact. Thus, the sign of the new velocity of the object would be negative- the opposite of that of the initial velocity. The new velocity would be (-4.0\; {\rm m\cdot s^{-1}}).

Thus, the change in the velocity of the mass would be:

\begin{aligned}& (\text{Change in Velocity}) \\ =\; & (\text{Final Velocity}) - (\text{Initial Velocity}) \\ =\; & (-4.0\; {\rm m\cdot s^{-1}}) - (6.0\; {\rm m\cdot s^{-1}}) \\ =\; & (-10\; {\rm m\cdot s^{-1})\end{aligned}.

The change in the linear momentum of the mass would be:

\begin{aligned} & \text{change in momentum} \\ =\; & (\text{mass}) \times (\text{change in velocity}) \\ =\; & 0.58\; {\rm kg} \times (-10\; {\rm m\cdot s^{-1}}) \\  =\; & (-5.8\; {\rm kg \cdot m \cdot s^{-1}})\end{aligned}.

Thus, the magnitude of the change of the linear momentum would be 5.8\; {\rm kg \cdot m \cdot s^{-1}}.

7 0
3 years ago
The frequency of the musical note F#3 is 1.85x102 hertz. What is its period?
g100num [7]

The period of the musical note is \text { 5. } 4 \times 10^{-3} seconds.

Answer: Option A

<u>Explanation:</u>

The frequency is defined as the number of oscillations or a complete cycle of wave occurred in a given time interval. So the frequency is inversely proportional to the time period. Thus the mathematical representation of frequency with time period is

               \text {Frequency}=\frac{1}{\text {Time period }}

As the frequency is given as 1.85 \times 10^{2} \mathrm{Hz}, the time period can be found as

               \text { Time period }=\frac{1}{\text { Frequency }}

Thus,

               \text { Time period }=\frac{1}{1.85 \times 10^{2}}=5.4 \times 10^{-3} \mathrm{s}

Thus the time period for the frequency of the musical note is \text { 5. } 4 \times 10^{-3} seconds.

5 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Ne4ueva [31]

My teacher taught me that besides the type of wave, wavelength doesn't change unless you shorten the wave, and she used string as an example. Making the string shorter causes the wavelength to decrease so it can't be B. Your answer is A

8 0
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