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Monica [59]
3 years ago
7

A 5.00-kg howler monkey is swinging due east on a vine. It overtakes and grabs onto a 6.00-kg monkey also moving east on a secon

d vine. The first monkey is moving at 10.0 m/s at the instant it grabs the second, which is moving at 7.00 m/s. 1) After they join on the same vine, what is their common speed
Physics
1 answer:
notka56 [123]3 years ago
5 0

Answer:

8.36 m/s

Explanation:

From the law of conservation of momentum,

Total momentum of the monkeys before grab = Total momentum after grab

mu+m'u' = V(m+m')................... Equation 1

Where m = mass of the first money, m' = mass of the second monkey, u = initial velocity of the first monkey, u' = initial velocity of the second monkey, V = Common velocity of both monkeys.

make V the subject of the equation

V = [mu+m'u']/(m+m')................ Equation 2

Given: m = 5 kg, m' = 6 kg, u = 10 m/s, u' = 7 m/s

Substitute into equation 2

V = [5×10+6×7]/(5+6)

V = [50+42]/11

V = 92/11

V = 8.36 m/s

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A sample of copper with a mass of 1.80 kg, initially at a temperature of 150.0°C, is in a well-insulated container. Water at a t
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the mass of water is 0.3 Kg

Explanation:

since the container is well-insulated, the heat released by the copper is absorbed by the water , therefore:

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since Q = m * c * ( T eq - Ti ) , where m = mass, c = specific heat, T eq = equilibrium temperature and Ti = initial temperature

and denoting w as water and co as copper :

m w * c w * (T eq - Tiw) = - m co * c co * (T eq - Ti co) =  m co * c co * (T co - Ti eq)

m w = m co * c co * (T co - Ti eq) / [ c w * (T eq - Tiw) ]

We take the specific heat of water as c= 1 cal/g °C = 4.186 J/g °C . Also the specific heat of copper can be found in tables → at 25°C c co = 0.385 J/g°C

if we assume that both specific heats do not change during the process (or the change is insignificant)

m w = m co * c co * (T eq - Ti co) / [ c w * (T eq - Tiw) ]

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m w= 0.3 kg

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4 years ago
A motion sensor acts as a transmitter when it sends out pulses and as a receiver when it listens for echoes. The delay ∆t betwee
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Answer:

1.526 m

Explanation:

The motion sensor sends sound waves in air which travels at a speed of 343 m per second at 20 degree. If d be the distance of the reflecting object

total distance travelled = 2d

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velocity v  = 2d / t

343 = 2 d / (8.9 x 10⁻³)

d = 1.526 m

4 0
3 years ago
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