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Monica [59]
3 years ago
7

A 5.00-kg howler monkey is swinging due east on a vine. It overtakes and grabs onto a 6.00-kg monkey also moving east on a secon

d vine. The first monkey is moving at 10.0 m/s at the instant it grabs the second, which is moving at 7.00 m/s. 1) After they join on the same vine, what is their common speed
Physics
1 answer:
notka56 [123]3 years ago
5 0

Answer:

8.36 m/s

Explanation:

From the law of conservation of momentum,

Total momentum of the monkeys before grab = Total momentum after grab

mu+m'u' = V(m+m')................... Equation 1

Where m = mass of the first money, m' = mass of the second monkey, u = initial velocity of the first monkey, u' = initial velocity of the second monkey, V = Common velocity of both monkeys.

make V the subject of the equation

V = [mu+m'u']/(m+m')................ Equation 2

Given: m = 5 kg, m' = 6 kg, u = 10 m/s, u' = 7 m/s

Substitute into equation 2

V = [5×10+6×7]/(5+6)

V = [50+42]/11

V = 92/11

V = 8.36 m/s

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Answer:

A

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    The distance in degrees  is  \theta =2529 ^ o

   The distance in radian is  \theta_{radian } = 44.15 \ rad

B

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Explanation:

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  The diameter of the pie is  d = 10.00 \ in

  The distance covered by the rim  is  D = 208  \ in

   The number which the pie is divided into  is  k = 5

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=>  r = \frac{10}{2}

=>  r = 5 \ in

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=>  \theta = 7 * 360

=>  \theta =2529 ^ o

Generally converting to  radian

   \theta_{radian } = \frac{\theta * \pi}{180 }

=>\theta_{radian } = \frac{2520 * 3.142 }{180}

=>\theta_{radian } = 44.15 \ rad

Generally the angular size of one piece of the pie is  

      \theta_a = \frac{2 * \pi }{ k}

=> \theta_a = \frac{2 * 3.142}{ 5}

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