I think 3 is 1.5...i kinda hope that helps for one
Answer:
Explanation:
There are 3 main forces at work here, gravity, normal and friction. The gravity pulls the car straight down and is what keeps the car on the ground. Normal force is straight up from the points where the car is touching, so since the wheels are the only parts of the car touching the street, this is where all the normal force is. Friction force opposes any and all motion, the car wants to slide down the hill and would slide down the hill if there was no friction, so the friction force is in the opposite direction of the cars intended motion.
(a) What is
the potential energy: PE = -G * M * m/r
Where: M is the mass of the earth which is 5.98 * 10^24 kg.
m is the mass of the satellite.
r is the space from the center of the earth to the satellite
To conclude this distance add the radius of the earth to the
altitude. Radius of the earth is 6.38 * 10^6 meters.
r = 6.38 * 10^6 + 2.02 * 10^6 = 8.38 * 10^6
PE = 6.67 * 10^-11 * 5.98 * 10^24 * 99/8.38 * 10^6 =
4.71240095 * 10^9 J
(b) magnitude of the gravitational force exerted by the
Earth
Fg = G * M * m/r^2
Fg = 6.67 * 10^-11 * 5.98 * 10^24 * 99/(8.38 * 10^6)^2 =
562.3078873 N
(c) There are no other forces that the satellite exert on
the Earth. So therefore, it is 0.
Answer: OLEDs
Explanation:
The nanotechnology uses the surface of the carbon materials to generate the electricity. The evaporation of water on the surface of carbon materials helps in generation of electrical energy due to generation of thermal energy.
OLEDs can be defined as solid-state devices that comprises of organic molecules like carbon that will create electricity by exposing a surface for generation of thermal energy.
Answer:
The final pressure of oxygen gas is 8.33 atm.
Explanation:
From the given data
V=26 m^3 or 26000 L
T1=270K
T2=440K
n1=6000 moles
R=0.0821 L.atm/molK
Now from the ideal gas equation
As the options given are not defined in which unit thus the final pressure of oxygen gas is 8.33 atm.
<em>*The options are provided for a different question where </em>
