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Alex787 [66]
2 years ago
11

A bucket filled with water has a mass of 70kg and is hanging from a rope that is wound around a 0.054 m radius stationary cylind

er. If the cylinder does not rotate and the bucket hangs straight down, what is the magnitude of the torque the bucket produces around the center of the cylinder?
Physics
1 answer:
guajiro [1.7K]2 years ago
3 0

Answer:

T = 37.08 [N*m]

Explanation:

We must remember that torque is defined as the product of a force by a distance. This distance is measured from the point of application of force to the center of rotation of the rotating body.

The force is equal to the product of mass by gravitational acceleration.

F=m*g\\F=70*9.81\\F=686.7[N]

Now the torque can be calculated:

T=F*r\\T=686.7*0.054\\T=37.08[N*m]

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A 500kg car is driving through a neighborhood at 20m/s. Then the car hits a speed bump which causes it to slow to 15m/s. What wa
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Based on the formula for calculating impulse, the impulse of the speed bump to the car is 2500 Ns.

<h3>What is the impulse of the speed bump?</h3>

  • Impulse = change in momentum
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Change in momentum = mu - mv

where u is initial velocity

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Impulse = 500 * 20  - 500 * 15

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Learn more about impulse at: brainly.com/question/297527

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3 years ago
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6 0
2 years ago
Numbered 8 nowwwwwww
amm1812

Torque =  r x F

|F| =  mg =  60 * 10 N = 600 N ( assuming g ~ 10m/s^2)

distance of fulcrum = torque / Force = 90/600 m = .15 m.

7 0
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