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ollegr [7]
3 years ago
9

The 2006 value of a car was $18,000. In 2016, it was worth $4000. If the annual percent of decay has been constant, what is the

annual percent of decay? Please show your work!
Mathematics
1 answer:
MArishka [77]3 years ago
7 0

Answer:

7.77% per year

Step-by-step explanation:

From 2006 to 2016 the price of the car went from $18.000 to $4.000. So it lose 77.77% of its value in 10 years.

To know the total percentage of decay in 10 years we use the rule of three.

If $18.000 represents %100

What percentage does $4000 represents?

($4000 * 100 / $18.000) = 22.22%

If the final value is 22.22% of the initial value, then it lose 77.77% of its value. (100% - 22.22% = 77.77%_

Given that the percent of decay was constant, the annual percent of decay is: 77.77% / 10 years = 7.77% per year.

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Which gives the correct values for points A, B, C, and D?
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Answer:

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Step-by-step explanation:

5 0
3 years ago
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A sandwich store charges a delivery fee to bring lunch to an office building. One office pays $33 for 4 turkey sandwiches. Anoth
shutvik [7]

Answer:

$12

Step-by-step explanation:

assuming that the cost of delivery is constant irrespective of the number ordered

Let the cost of sandwich be x

First office

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Second office

$61=8x+c

These two are simultaneous equation. Subtracting the equation of first office from the second office we obtain

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Therefore, x=28/4=7

The cost of delivery is 33-(4*7)=33-28=5

Therefore, one sandwich plus delivery costs 7+5=$12

5 0
3 years ago
A manufacturing company produces 3 different products A, B, and C. Three types of components, i.e., X, Y, and Z, are used in the
Murljashka [212]

Answer:

Step-by-step explanation:

Using the Excel Formula:

Decision    Variable        Constraint              Constraint

A                     65                          65                         100

B                     80                          80                         80

C                     90                         90                          90

                      14100                    300                        300

= (150 *B3)+(80*B4) +(65*B5)-(100-B3+80-B4+90-B5)*90

Now, we have:

Suppose A, B, C represent the number of units for production A, B, C which is being manufactured

                             A              B                  C                Unit price

Need of X          2                 1                   1                     $20

Need of Y           2                3                  2                    $30

Need of Z           2                2                  3                    $25

Price of  

manufac -      $200          $240            $220      

turing

Now,  for manufacturing one unit of A, we require 2 units of X, 2 units of Y, 2 units of Z are required.  

Thus, the cost or unit of manufacturing of A is:

$20 (2) + $30(2) + $25(2)

$(40 + 60 + 50)

= $150

Also, the market price of A = $200

So, profit = $200 - $150 = $50/ unit of A

Again;

For manufacturing one unit of B, we require 1 unit of X, 3 units of Y, and 2 units of Z are needed and they are purchased at $20, $30, and 425 each.

So, total cost of manufacturing a unit of B is:

= $20(1) + $30(3) + $25(2)

= $(20 + 90+50)

= $160

And the market price of B = $240

Thus, profit = $240- $160  

profit = $80

For manufacturing one unit of C, we have to use 1 unit of X, 2 unit of Y, 3 units of Z are required:

SO, the total cost of manufacturing a unit of C is:

= $20 (1) + $30(2) + $25(3)

= $20 + $60 + $25

= $155

This, the profit = $220 - $155 = $65

However; In manufacturing A units of product A, B unit of product B & C units of product C.

Profit  --> 50A + 80B + 65C

This should be provided there is no penalty for under supply of there is under supply penalty for A, B, C is $40

The current demand is:

100 - A

80 - B

90 - C respectively

So, the total penalty

{(100 - A) + (80 - B) +(90 - C) } + \$40

This should be subtracted from profit.

So, we have to maximize the profit  

Z = 50A + 80B + 65C = {(100 -A) + (80 - B) + (90 - C)};

Subject to constraints;

we have the total units of X purchased can only be less than or equal to 300 due to supplies capacity

Then;

2A + B +C \le 300 due to 2A, B, C units of X are used in manufacturing A, B, C units of products A, B, C respectively.

Next; demand for A, B, C will not exceed 100, 80, 90 units.

Hence;

A \le 100

B \le 80

C \le 90

 

and A, B, C \ge 0 because they are positive quantities

The objective is:

\mathbf{Z = 50A + 80B + 65 C - (100 - A + 80 - B + 90 - C) * 40}

A, B, C \to Decision Varaibles;

Constraint are:

A \le 100 \\ \\  B \le 100 \\ \\ C \le 90 \\ \\2A + B + C \le 300 \\ \\ A,B,C \ge 0

6 0
3 years ago
Please help me with this ASAP.
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<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>

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