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3 years ago

12

If d(x) = x2 - 7x - 7, find d(x - 1).

1 answer:

satela [25.4K]3 years ago

7 0

Answer: x^2-9x+1

Step-by-step explanation:

x^2-7x-7 d(x-1)

(you would just replace x to (x-1)

(x-1)^2-7(x-1)-7

(solve by square rooting (x-1)(x-1) then foil)

x^2-9x+1

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I'll give you brainliest! Just need help with 5-10! (Least common factors)

umka2103 [35]

Answer:

60
30
48
42
45
55

Step-by-step explanation:

5.

$12,\:30\\\\\mathrm{Prime\:factorization\:of\:}12:\quad 2\times\:2\times\:3\\\mathrm{Prime\:factorization\:of\:}30:\quad 2\times\:3\times\:5\\\\=2\times\:2\times\:3\times\:5\\\\=60$

6.

$6,\:10\\\\\mathrm{Prime\:factorization\:of\:}6:\quad 2\times\:3\\\mathrm{Prime\:factorization\:of\:}10:\quad 2\times \:5\\\\=2\times \:3\times \:5\\\\=30$

7.

$16,\:24\\\\\mathrm{Prime\:factorization\:of\:}16:\quad 2\times \:2\times\:2\times\:2\\\mathrm{Prime\:factorization\:of\:}24:\quad 2\times\:2\times\:2\times\:3\\\\=2\times\:2\times\:2\times\:2\times\:3\\\\=48$

8.

$14,21\\\\\mathrm{Prime\:factorization\:of\:}14:\quad 2\times\:7\\\mathrm{Prime\:factorization\:of\:}21:\quad 3\times\:7\\\\=2\times\:7\times\:3\\\\=42$

9.

$9,15\\\\\mathrm{Prime\:factorization\:of\:}9:\quad 3\times\:3\\\mathrm{Prime\:factorization\:of\:}15:\quad 3\times\:5\\\\=3\times\:3\times\:5\\\\=45$

10.

$5,\:11\\\\\mathrm{Prime\:factorization\:of\:}5:\quad 5\\\mathrm{Prime\:factorization\:of\:}11:\quad 11\\\\=5\times \:11\\\\=55$

5 0

3 years ago

Which is the correct input-output table for the function f(x) = 7 – 4.5x?

Naddika [18.5K]

Step 1: Divide both sides by x.<span><span><span>fx</span>x</span>=<span><span><span>−<span>4.5x</span></span>+7</span>x</span></span><span>f=<span><span><span>−<span>4.5x</span></span>+7</span>x</span></span>Answer:f=<span><span><span>−<span>4.5x</span></span>+7</span><span>x</span></span>

3 0

3 years ago

Read 2 more answers

Please i need help !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

tekilochka [14]

Answer:

limeted government or rule of law i think sorta mayby kindaa

4 0

2 years ago

Use the rules of exponents to evaluate and simplify the following expression. Type all without negative exponents. Do not distri

Rainbow [258]

We are given (xy)^(-3).

This leads to 1/(xy)^3.

You see, going from the top to the bottom alters the sign of the exponent to its opposite.

ANSWER: 1/(x^3•y^3)

Did you follow?

5 0

3 years ago

Given the set of vertices, determine whether parallelogram ABCD is a rhombus, rectangle or square. List all that apply. A(7,-4),

Sloan [31]

Given:

Vertices of a parallelogram ABCD are A(7,-4), B(-1,-4), C(-1,-12), D(7, -12).

To find:

Whether the parallelogram ABCD is a rhombus, rectangle or square.

Solution:

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, we get

$AB=\sqrt{(-4-(-4))^2+(-1-7)^2}$

$AB=\sqrt{(-4+4)^2+(-8)^2}$

$AB=\sqrt{0+64}$

$AB=8$

Similarly,

$BC=\sqrt{(-1-(-1))^2+(12-(-4))^2}=8$

$CD=\sqrt{(7-(-1))^2+(-12-(-12))^2}=8$

$AD=\sqrt{(7-7)^2+(-12-(-4))^2}=8$

All sides of parallelogram are equal.

$AC=\sqrt{(-1-7)^2+(-12-(-4))^2}=8\sqrt{2}$

$BD=\sqrt{(7-(-1))^2+(-12-(-4))^2}=8\sqrt{2}$

Both diagonals are equal.

Since, all sides are equal and both diagonals are equal, therefore, the parallelogram ABCD is a square.

We know that, a square is special case of rectangles and rhombus.

So, parallelogram ABCD is a rhombus, rectangle or square. Therefore, the correct option is c.

7 0

3 years ago