Answer:
158.5g Zn are produced
Explanation:
To solve this question we have to find the moles of Aluminium. With the moles of Aluminium and the balanced reaction we can find the moles of Zn and its mass as follows:
<em>Moles Al -Molar mass: 26.98g/mol</em>
43.6g Al* (1mol/26.98g) = 1.616 moles Al
<em>Moles Zn:</em>
1.616 moles Al * (3mol Zn / 2mol Al) =
2.424 moles Zn are produced
<em>Mass Zn -Molar mass: 65.38g/mol-</em>
2.424 moles Zn * (65.38g / mol) =
<h3>158.5g Zn are produced</h3>
In the titration of acetic acid with a strong base NaOH, the concentration of acetic acid is determined using the volume and molar concentration of NaOH used for titrating the vinegar solution. NaOH and acetic acid react in 1:1 mole ratio.
When a drop of the strong base, dispensed from the buret sticks to the walls of the Erlenmeyer flask but is not washed into the flask containing vinegar, it means that the recorded value of NaOH dispensed will be higher than the actual value required for the titration. So, the reported moles of acetic acid calculated from the moles of NaOH used for the titration will be higher. So, the mass percent reported will be higher than the actual value.
Answer:
$13,500
Explanation:
The differential analysis of the proposal to replace the commercial oven is shown below:-
The Total differential decrease in cost = Annual maintenance cost reduction × Number of years applicable
= $23,000 × 5
= $115,000
Inflow cash = The Total differential decrease in cost + Proceeds from sale of equipment
= 115,000 + $8,500
= $123,500
The Net differential decrease in cost from replacing equipment = Inflow cash - Cost of new equipment
= $123,500 - $110,000
= $13,500
Answer:
I would go for number 5 . It sounds more logical to me.
Answer:
D. 0.75 grams
Explanation:
The data given on the iridium 182 are;
The half life of the iridium 182, = 15 years
The mass of the sample of iridium, N₀ = 3 grams
The amount left, N(t) after two half lives is given as follows;
For two half lives, t = 2 ×
∴ t = 2 × 15 = 30
∴ The amount left, N(t) = 0.75 grams