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lozanna [386]
4 years ago
15

A solution is made by mixing of 42.g water and 77.g of acetic acid HCH3CO2. Calculate the mole fraction of water in this solutio

n.
Chemistry
1 answer:
KengaRu [80]4 years ago
6 0

Moles of H_2O ,

n_{H_2O}=\dfrac{42}{2\times 1 + 16}=\dfrac{42}{18}\\\\n_{H_2O}=2.33\ moles

Moles of acetic acid HCH_3CO_2 ,

n_{A.A}=\dfrac{77}{1 + 12 + 3 + 12 + 16\times 2}=\dfrac{77}{60}\\\\n_{A.A}=1.28\ moles

Mole fraction of water :

M.F_{H_2O}=\dfrac{n_{H_2O}}{n_{H_2O}+n_{A.A}}\\\\M.F_{H_2O}=\dfrac{2.33}{2.33+1.28}\\\\M.F_{H_2O}=0.645

Therefore, mole fraction of water in this solution is 0.645 .

Hence, this is the required solution.

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Explanation: The doublets behind the 7 ppm belongs to the

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4 years ago
1-Bromopropane is treated with each of the following reagents. Draw the major substitution product if the reaction proceeds in g
sammy [17]

Answer:

Explanation:

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Primary alkyl - halide undergo SN2 mechanism. This nucleophilic reaction needs to be a strong alkyl halide , such as 1-Bromopropane used  otherwise it will result to a reactive mechanism if a weak electrophile is used.

However, the critical and the main objective here is to Draw the major substitution product if the reaction proceeds in good yield. If no reaction is expected or yields will be poor, draw the starting material in the box. If a charged product is formed, be sure to draw the counterion.

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Answer:

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5. Change of smell

In the reaction of hydrogen peroxide and potassium iodide, the solution quickly rises which shows the formation of gas. This means it is a chemical reaction.

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Al^{3+}: O^{2-}=2:3; This is correct because if charges are like this, you must find the least common factor in order to know the ratio. The LCF is 6, therefore, for the atom with a 3+ charge, you need 2 of them, and for the atom with a 2- charge, you need 3 of them. This keeps the charge neutral.

7 0
3 years ago
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