Answer:
0.271 M NO₃⁻
Explanation:
To find the molarity of the nitrate ion (NO₃⁻), you need to (1) convert grams to moles (via molar mass), then (2) convert moles Al(NO₃)₃ to moles NO₃⁻, then (3) convert mL to L, and then (4) calculate the molarity. When (Al(NO₃)₃) dissolves in water, it dissociates into 3 nitrate ions. The final answer should have 3 sig figs.
(Steps 1 + 2)
Molar Mass (Al(NO₃)₃): 26.982 g/mol + 3(14.007 g/mol) + 9(15.998 g/mol)
Molar Mass (Al(NO₃)₃): 212.985 g/mol
1 Al(NO₃)₃ = 1 Al³⁺ and 3 NO₃⁻
6.25 g Al(NO₃)₃ 1 mole 3 moles NO₃⁻
------------------------- x ----------------- x ----------------------- = 0.0880 moles NO₃⁻
212.985 g 1 mole Al(NO₃)₃
(Steps 3 + 4)
325.0 mL / 1,000 = 0.3250 L
Molarity = moles / volume
Molarity = 0.0880 moles / 0.3250 L
Molarity = 0.271 M
Answer:
The volume at STP of 0,765 moles of carbon monoxide gas is 17, 125 L.
Explanation:
We use the ideal gas formula, with the constant R = 0.082 l atm / K mol. The STP conditions are : 1 atm pressure and 273 K temperature. Solve for the formula, V (volume):
PV=nRT ---> V= (nRT)/P
V= (0,765 mol x0,082 l atm/ K mol x 273 K)/ 1 atm
<em>V= 17, 12529 L</em>
Answer: The vapor pressure of a mixture of 80 g of ethanol and 97 g of methanol at 293 K is 78.3 torr.
Explanation:
According to Raoult's law, the vapor pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the vapor pressure of that component in the pure state.
and 
where, x = mole fraction in solution
= pressure in the pure state
According to Dalton's law, the total pressure is the sum of individual pressures.
moles of ethanol=
moles of methanol= 
Total moles = moles of ethanol + moles of methanol = 1.7 +3.0 = 4.7
Thus the vapor pressure of a mixture of 80 g of ethanol and 97 g of methanol at 293 K is 78.3 torr.
Answer:
When volume is kept constant (kept the same), Gay-Lussac's law states that the pressure of gas varies directly with the temperature of the gas. The equation would be 
, Where P is the pressure (in atm) and T is the temperature (in K°).
Explanation:
Attached is a word document that contains a picture of the drawing as well as the explanation. Let me know if the picture is not showing up or if my hand writing is too hard to read so that I can type the explanation in the comments for this answer.
the major points for the answer was that the Sn²⁺ is reduced while the Cr is oxidized and that the Sn electrode is the cathode while the Cr electrode is the anode. The electrons travel from the anode to the cathode while the anions travel from the cathode to the anode.
I hope this helps. Let me know if anything is unclear or if you want me to explain anything further.
