Answer:
1250 m²
Step-by-step explanation:
Let x and y denote the sides of the rectangular research plot.
Thus, area is;
A = xy
Now, we are told that end of the plot already has an erected wall. This means we are left with 3 sides to work with.
Thus, if y is the erected wall, and we are using 100m wire for the remaining sides, it means;
2x + y = 100
Thus, y = 100 - 2x
Since A = xy
We have; A = x(100 - 2x)
A = 100x - 2x²
At maximum area, dA/dx = 0.thus;
dA/dx = 100 - 4x
-4x + 100 = 0
4x = 100
x = 100/4
x = 25
Let's confirm if it is maximum from d²A/dx²
d²A/dx² = -4. This is less than 0 and thus it's maximum.
Let's plug in 25 for x in the area equation;
A_max = 25(100 - 2(25))
A_max = 1250 m²
-8+b2-(5+b2). Since the - is outside the paranthesis the signs inside change: -8+b2-5-b2. -8-5=-3, b2-b2=0. Your answer: -3 :)
(4x+3y=-13) * 2
(-5x+2y=-24)*3
_____________
8x+6y=-26
-
-15x+6y=-72
___________
23x=46
X=2
18 servings of soup he can make with the potatoes!
Answer:
Step-by-step explanation:
i might be wrong but it might be 65
