My favorite strategy is the criss cross method.

Take the numerator of the first fraction (2), and the denominator of the second fraction (8) and multiply them. The value 16 is now up on the left side, imaginary. (ALWAYS PUT THE PRODUCT ON THE SIDE WITH THE NUMERATOR) Now multiply the other diagonal. 3(7)=21. The 21 is on the right side. Now do 16 ? 21
Is it <, >, or =? The answer is <
it would be 40.22 but it's a repeating decimal
Answer: im pretty sure its 5 to the second power so the third one
Step-by-step explanation:
Answer:
1/4
Step-by-step explanation:
Simplify the following:
(3^2/6^2)/(2^2/2^2)
Multiply the numerator by the reciprocal of the denominator, (3^2/6^2)/(2^2/2^2) = 3^2/6^2×2^2/2^2:
(3^2×2^2)/(6^2×2^2)
(3^2×2^2)/(6^2×2^2) = 2^2/2^2×3^2/6^2 = 3^2/6^2:
3^2/6^2
6^2 = 36:
3^2/36
3^2 = 9:
9/36
The gcd of 9 and 36 is 9, so 9/36 = (9×1)/(9×4) = 9/9×1/4 = 1/4:
Answer: 1/4
Undefined
Order of matrix Q is 4 by 3
whereas order of R is 4by 4
In order to add two matrices , they should be of same order.