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MArishka [77]
3 years ago
12

Mel randomly selects a coin 200 times selecting a penny 45 times A. The experimental probability of 9 selecting a penny is 40 B.

The theoretical probability of 6 selecting a penny is 25 C. The difference between the experimental 1 and theoretical probability is 10 What is the wrong answer?​
Mathematics
1 answer:
jek_recluse [69]3 years ago
3 0

Answer:

the wrong answer is C, but the right answer is A

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John and Annie have two distinguishable ponds. Initially, each of the ponds contains four ducks and five geese. John first picks
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Answer: 4/9

Step-by-step explanation:

The probability that annie picks a duck Pt= the probability of picking a duck without accounting for the added one (Po)+ probability of picking the added bird and it's a duck(Pi)

Pt = Po+Pi

Since the total number of birds in the right pond is 10 after the addition of one by john

Po= 4/10

Pi= the of john adding a duck × the probability of annie picking the added bird

Pi= 4/9 × 1/10

Pi = 4/90

Pt= 4/10 + 4/90

Pt = (36+4)/90

Pt=40/90

Pt= 4/9

(This implies that the probability of picking a duck remain the same even after the addition of one bird from the left ponds because they both have equal proportions of duck and geese i.e the initial number of duck and geese in both right and left ponds are 4 and 5 respectively)

Thanks.

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Solve for x:<br> 18x + 3x + 4 - 5 = 5(4x – 9
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Answer:
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\bf \cfrac{18}{32}\implies \cfrac{2\cdot 3\cdot 3}{2\cdot 2\cdot 2\cdot 2\cdot 2}\implies \cfrac{3\cdot 3}{2\cdot 2\cdot 2\cdot 2}\implies \boxed{\cfrac{9}{16}}\qquad \checkmark \\\\[-0.35em] ~\dotfill\\\\ \cfrac{27}{48}\implies \cfrac{3\cdot 3\cdot 3}{2\cdot 2\cdot 2\cdot 2\cdot 3}\implies \cfrac{3\cdot 3}{2\cdot 2\cdot 2\cdot 2}\implies \boxed{\cfrac{9}{16}}\qquad \checkmark

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<span>the abstract science of number, quantity, and space.

</span>
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