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BARSIC [14]
3 years ago
14

The figure below shows rectangle ABCD.

Mathematics
2 answers:
kipiarov [429]3 years ago
4 0

Answer: We can find out the missing statement with help of below explanation.

Step-by-step explanation:

We have a rectangle ABCD with diagonals AC and BD ( shown in given figure.)

We have to prove: Diagonals AC and BD bisect each other.

In triangles, AED and BEC.

\angle ADB \cong \angle CBD ( By alternative angle theorem)

AD\cong BC ( Because ABCD is a rectangle)

\angle CAD\cong \angle ACB  ( By alternative angle theorem)

By ASA postulate,\triangle AED\cong \triangle BEC

By CPCTC, BE\cong ED and CE\cong EA

⇒ BE= ED and CE=EA

By the definition of bisector, AC and BD bisect each other.


AnnyKZ [126]3 years ago
3 0

Answer:

To Prove the diagonals of the rectangle bisect each other, Statement with reason is given:

Statement  ABCD is a rectangle.

Reason:Given

Statement

:Opposite sides are parallel.(AB║DC)

Reason: Definition of a Parallelogram

Statement

:Opposite sides are parallel.(AD║BC)

Reason: Definition of a Parallelogram

Statement

:∠CAB ≅ ∠ ACB

Reason: Alternate interior angles theorem

Statement

: ∠ADB ≅ ∠CBD

Reason:  Alternate interior angles theorem

Option D:∠CAB ≅ ∠ ACB

In ΔAED and ΔBEC

∠CAB ≅ ∠ ACB→→Alternate interior angle,as AB║DC.

∠ADB ≅ ∠CBD→→Alternate interior angle,as AD║BC.

AD=BC→→Opposite sides in a rectangle are equal.

ΔAED ≅ ΔBEC⇒⇒[ASA]

AE=EC→[CPCTC]

BE=ED→[CPCTC]

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