<h2>Answer:</h2>
<u>In ΔQRS and ΔQLK</u>,
QR/QL = QS/QK
28/4 = 28/4
7/1 = 7/1 --[1]
<u>AngleLQK and AngleRQS are equal</u> (VOA)
<u>Two sides are in same proportion and the included angle is common (SAS) . Hence both the triangles are similar</u>.
[A] ΔQRS ~ ΔQLK by SAS similarity.
The answer should be A because when you multiply two negatives it comes out positive
Answer:
<h2>This equation has no natural roots.</h2>
Step-by-step explanation:
I'll proceed by evaluating total length and surface area by scanned images. For measurements, I suggest to use winrhizo or any similar software. In this case the most important thing to think about is to use the appropiate acquisition parameters, I mean, to set a good resolution during scanning. Pixels of the aquired image should be smaller than root hairs diameter. Therefore, let me try to suggest you a good acquisition resolution. Making a quick research, it seems that hair root diameters range between 0,012 and 0,017 mm, so I suggest a resolution that will give a pixel dimension of 0,002 mm. Root hair diameters should be composed by 6-8 pixels, that is enough for winrhizo measurements. Resolution is measured in dpi, so in "dots/pixel per inch". A inch is 25,4 mm. We need pixels with a diameter of 0,002 mm, so in 25,4 mm we found 12700 pixels. That means 12700 dpi. It's a very high resolution, you need a good scanner and much space in your computer.
Answer:
∠SQR = 1/2 m ∠SR = 1/2 x 86 = 43°
