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Elenna [48]
3 years ago
7

I NEED HELP ASAP -7t=175 what is the answer

Mathematics
2 answers:
Leto [7]3 years ago
4 0

Answer:

t = -25

Step-by-step explanation:

Divide both sides by -7 so that the variable x could be on its own

-7/-7 t = 175/-7

t = -25

Liula [17]3 years ago
3 0

Answer:

T= -25

Step-by-step explanation:

175 divided by -7 is -25.

its -25 because a negative and a negative equals a positive.

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Answer:

Area = 6.25\pi ft^2

Step-by-step explanation:

Area = \pi \\r^{2}

The diameter is 5 feet.  That makes the radius 2.5 feet

Area = \pi \\r^{2}

Area = \pi \\2.5^{2}

Area = 6.25\pi ft^2

6 0
2 years ago
Write a function rule for the following arithmetic sequence and use it to find the 224th term. Show your work.
zavuch27 [327]

Answer:

671  is the 224th term of the given series

Step-by-step explanation:

The given sequence is

2,5,8,11....

First term that is 2

common difference that is 3

we have to find 224th term

That is n =224

using a_n=a+(n-1)d

a_{224}=2+(224-1)3

On solving the above equation we get

a_{224}=671

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5 0
3 years ago
Read 2 more answers
Round 1.965 to the nearest tenth.
riadik2000 [5.3K]

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Step-by-step explanation:

5 0
3 years ago
ABC Auto Insurance classifies drivers as good, medium, or poor risks. Drivers who apply to them for insurance fall into these th
Misha Larkins [42]

Answer:

a.P(E_1/A)=0.0789

b.P(E_2/A)=0.395\

c.P(E_3/A)=0.526

Step-by-step explanation:

Let E_1,E_2,E_3 are the events that denotes the good drive, medium drive and poor risk driver.

P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20

Let A be the event that denotes an accident.

P(A/E_1)=0.01

P(A/E_2=0.03

P(A/E_3)=0.10

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem,P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}

We have to find P(E_1/A)

Using the Bayes theorem

P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}

Substitute the values then we get

P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}

P(E_1/A)=0.0789

b.We have to find the probability Mr.Brophy is a medium driver

P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395

c.We have to find the probability Mr.Brophy is a poor driver

P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526

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4 years ago
Which quantity is unknown
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