Solve for y by setting one equation =to X after that you can substitute the equation into the other one let's set the first one in X= FORM
X-7y=10
-2x+14y=-20
Add 7y to both sides of the first equation to let x stand alone
X=7y+10
Now you can substitute x on the second equation
-2 (7y+10)+14y=-20
Distribute
-14y-20+14y=-20
Add and simplify
Us cancel out =0
-20=-20
0=0
They are the same equations you can also divide the second equation by -2 which would make it look like this
X-7y=10
-2 (x-7y=10)
Let me know if I have answered your question
When u have an outlier, u want to use the median.....in this case, the median is 4
Answer: Hello your question is missing some details but I will provide a general solution based on the scope of the problem and you can plugin the missing value
answer = Volume of rectangular prism box / volume of cube
Step-by-step explanation:
To determine the number of Dice that will fit in the rectangular prism box
First : calculate the volume of the cube box ( dice )
volume of a Cube box : V = L^3 where L = side length
next : calculate the volume of the rectangular prism box
volume of rectangular prism box = L * b * h
L= length , b = width , h = height
final step : Divide the volume of the rectangular prism box by the volume of the cube box ( dice )
= ( L * b * h ) / ( L^3 )
![\bf \qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ y = 4\frac{2}{3}x\qquad \qquad yes\qquad \checkmark\qquad \qquad k = 4\frac{2}{3} \\\\[-0.35em] ~\dotfill\\\\ y=3(x-1)\implies \stackrel{\textit{distributing}}{y=3x-3}\qquad \qquad yes\qquad \checkmark \qquad \qquad k=3](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Cqquad%20%5Ctextit%7Bdirect%20proportional%20variation%7D%20%5C%5C%5C%5C%20%5Ctextit%7B%5Cunderline%7By%7D%20varies%20directly%20with%20%5Cunderline%7Bx%7D%7D%5Cqquad%20%5Cqquad%20y%3Dkx%5Cimpliedby%20%5Cbegin%7Barray%7D%7Bllll%7D%20k%3Dconstant%5C%20of%5C%5C%20%5Cqquad%20variation%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20y%20%3D%204%5Cfrac%7B2%7D%7B3%7Dx%5Cqquad%20%5Cqquad%20yes%5Cqquad%20%5Ccheckmark%5Cqquad%20%5Cqquad%20k%20%3D%204%5Cfrac%7B2%7D%7B3%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20y%3D3%28x-1%29%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bdistributing%7D%7D%7By%3D3x-3%7D%5Cqquad%20%5Cqquad%20yes%5Cqquad%20%5Ccheckmark%20%5Cqquad%20%5Cqquad%20k%3D3)
bear in mind that, direct proportional equations have a y-intercept.
for y = kx, is pretty much y = kx + 0, where 0 = y-intercept.
and the "k" constant of proportionality, is pretty much just its slope.
