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3 years ago

In a class 30 of students, 5 are female and 23 have an A in the class. There are

Mathematics

1 answer:

djverab [1.8K]3 years ago

5 0

Answer:

20/30

Step-by-step explanation:

Five girls plus five boys equals ten, thirty minus ten equals twenty.

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The radius of a circle is 8 what is the area of the circle? pls show work

topjm [15]

Answer:

201.06

Step-by-step explanation:

A=πr2=π·82≈201.06193

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2 years ago

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2 less then 3 times a number is 9

Masteriza [31]

$\huge\boxed{\text{As an expression:}\ 3x-2=9}$

$\huge\boxed{\text{Solved for x:}\ x=\frac{11}{3}}$

Let's start with " $3$ times a number". We will use $x$ to represent the number. $3x$

" $2$ less than" is next. $-2$

Finally, "is $9$ ". $=9$

Put it all together to get an expression. $\boxed{3x-2=9}$

Now, let's solve for the unknown number.

Add $2$ on both sides of the equation. $3x=11$

Divide both sides of the equation by $3$ to isolate $x$ . $x=\boxed{\frac{11}{3}}$

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2 years ago

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-3x=x-(6-2x) solve it

frutty [35]

Answer:

x=1

Step-by-step explanation:

-3x=x-(6-2x)

-3x=x-6+2x

-3x=3x-6

6=3x+3x

6=6x

x=6/6

x=1

Best answer if it helped, please

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2 years ago

Two roots of a 3-degree polynomial equation are 5 and -5. Which of the following cannot be the third root of the equation? 0 -5i

sammy [17]

Answer:

-5i and 5i cannot be roots of the equation, since they are complex.

Step-by-step explanation:

A 3-degree polynomial equation must have 3 roots, if one of its roots is a complex number, then its conjugate must also be a root of the function. The problem already stated two roots, which are reals, therefore the last root must also be real. Using this line of thought we know that -5i and 5i cannot be roots of the equation, since they're complex.

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3 years ago

Find the volume of a cube with a side length of 12 feet.

konstantin123 [22]

Answer: 1728

Step-by-step explanation: 12x12x12

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2 years ago

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