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ddd [48]
3 years ago
11

To simplify the conceptual design, most higher-order relationships are decomposed into appropriate equivalent _____ relationship

s whenever possible.A) unary.B) binary.C) strong.D) weak.
Computers and Technology
1 answer:
LenaWriter [7]3 years ago
5 0

Answer: binary

Explanation:

Conceptual design refers to the early phase of the design process, whereby the outlines of function are articulated. The conceptual design consist of the design of processes, interactions, and strategies. It is the first stage in the database design process.

The output of the conceptual design process describes the main data entities, and constraints of a particular problem domain. To simplify the conceptual design, most higher-order relationships are decomposed into appropriate equivalent binary relationships whenever possible.

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Can you answer this question?
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Answer:

To do this you'll need to use malloc to assign memory to the pointers used.  You'll also need to use free to unassign that memory at the end of the program using the free.  Both of these are in stdlib.h.

#include <stdlib.h>

#include <stdio.h>

#define SIZE_X 3

#define SIZE_Y 4

int main(void){

       int **matrix, i, j;

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               matrix[i] = (int *)malloc(SIZE_Y * sizeof(int));

       }

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       for(i = 0; i < SIZE_X; i++){

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                       matrix[i][j] = SIZE_Y * i + j + 1;

               }

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       // print it out

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               for(j = 0; j < SIZE_X; j++){

                       printf("%d, %d:  %d\n", i, j, matrix[i][j]);

               }

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       // free the memory

       for(i = 0; i < SIZE_X; i++){

               free(matrix[i]);

       }

       free(matrix);

       return 0;

}

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Answer:

Check the explanation

Explanation:

In choosing the member and updating the replicate files the component or members in the replication group and preliminary members of the group as being taken as authoritative during the original replication.

For any changes you will be useing the sync -dfs replications and suspend-Dfs replication group.

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Answer:

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hope this helps! :)

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Explanation:

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