The area of a square of side s is
.. A = s^2
The area of a circle of diameter s is
.. A = (π/4)s^2
The area of the yellow region is the difference between these when s=5 ft, so is
.. (5 ft)^2*(1 -π/4) ≈ 5.4 ft^2
Remember
you can do anyting to an equaiton as long as you do it to both sidess
distributive property
a(b+c)=ab+ac
commutativ property
a+b=b+a
distribute
3(4x-2)=12x-6
12x-6=9+2x+5
add 6 both sides
12x+6-6=9+6+5+2x
12x+0=20+2x
minus 2x
10x=20
divide 10
x=2
S = Speed
D = Distance
T = Time
S = D/T
S = 50m/1/2
50 divided by 1/2 = 25
25 = 50/1/2
S = 25 m/min.
Answer:
x - 6
Step-by-step explanation:
I am unfamiliar with such algebra tiles, but logically that set of tiles tells me :
1 x, -1, -1, -1, -1, -1, -1
so,
1×x + 6×(-1) = x - 6
![\bf ~\hspace{10em}1\le x\le 5~\hspace{5em}\sqrt{x^3+36} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \sqrt{x^3+36}\implies \sqrt{x^{2+1}6^2}\implies \sqrt{x^2x6^2}\implies \sqrt{(6x)^2x}\implies 6x\sqrt{x} \\\\\\ \stackrel{\textit{x = 4}}{6(4)\sqrt{4}}\implies 24\sqrt{2^2}\implies 24\cdot 2\implies 48](https://tex.z-dn.net/?f=%5Cbf%20~%5Chspace%7B10em%7D1%5Cle%20x%5Cle%205~%5Chspace%7B5em%7D%5Csqrt%7Bx%5E3%2B36%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A%5Csqrt%7Bx%5E3%2B36%7D%5Cimplies%20%5Csqrt%7Bx%5E%7B2%2B1%7D6%5E2%7D%5Cimplies%20%5Csqrt%7Bx%5E2x6%5E2%7D%5Cimplies%20%5Csqrt%7B%286x%29%5E2x%7D%5Cimplies%206x%5Csqrt%7Bx%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Cstackrel%7B%5Ctextit%7Bx%20%3D%204%7D%7D%7B6%284%29%5Csqrt%7B4%7D%7D%5Cimplies%2024%5Csqrt%7B2%5E2%7D%5Cimplies%2024%5Ccdot%202%5Cimplies%2048)
that's how I read it.... to get some value between 1 and 5, namely 4, to make the expression a rational, well, 48 can be expressed as 48/1.
