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Dafna11 [192]
3 years ago
10

If the graphs of the linear equations in a system are the same line, what does that mean about the possible solution or solution

s of the system? А.) There is exactly one solution
B.) There is no solution.
C.) There are infiriitely many solutions
D.) The lines in a system cannot graph the same line.
((PLEASE HELPPP))​

Mathematics
1 answer:
kvasek [131]3 years ago
8 0
I think it’s c there are many solutions
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Indicate whether the statement is true of false.
yawa3891 [41]

The statement is false, as the system can have no solutions or infinite solutions.

<h3>Is the statement true or false?</h3>

The statement says that a system of linear equations with 3 variables and 3 equations has one solution.

If the variables are x, y, and z, then the system can be written as:

a_1*x + b_1*y + c_1*z = d_1\\\\a_2*x + b_2*y + c_2*z = d_2\\\\a_3*x + b_3*y + c_3*z = d_3

Now, the statement is clearly false. Suppose that we have:

a_1 = a_2 = a_3\\b_1 = b_2 = b_3\\c_1 = c_2 = c_3\\\\d_1 \neq d_2 \neq  d_3

Then we have 3 parallel equations. Parallel equations never do intercept, then this system has no solutions.

Then there are systems of 3 variables with 3 equations where there are no solutions, so the statement is false.

If you want to learn more about systems of equations:

brainly.com/question/13729904

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3 0
2 years ago
(PLEASE ANSWER + BRAINLIEST!!)
Licemer1 [7]
The answer is x=20.  Hope this helps.
8 0
3 years ago
Help, fast pls. I don't know how to do this and don't have notes for the class.
iogann1982 [59]

Step-by-step explanation:

according to the drawing,

for x = 0 => y = 12

the coordinates of y-intercept : (0, 12)

so, y = f(0) = 12

The correct answer is 12 only

5 0
2 years ago
Write down a differential equation of the form dy/dt = ay + b whose solutions have the required behavior as t → ∞. all other sol
nordsb [41]

The ODE has an equilibrium point at

\dfrac{\mathrm dy}{\mathrm dt}=ay+b=0\implies y=-\dfrac ba

We want y=2 to be an unstable equilibrium solution - in other words, we want all solutions with initial condition y(t_0)=c for c near 2 to diverge from y=2 - so -dfrac ba=2.

Divergence from y=2 would require that for y>2, any solution is increasing, and for y, and solution is decreasing. In order for that to happen, we need

\dfrac{\mathrm dy}{\mathrm dt}=ay+b>0\implies y>-\dfrac ba

if y>2, and

\dfrac{\mathrm dy}{\mathrm dt}=ay+b

if y.

Now we just pick a,b to satisfy these conditions. An easy choice is a=1, which forces b=-2, so that one possible ODE would be

\dfrac{\mathrm dy}{\mathrm dt}=y-2

I've attached a plot of the slope field to demonstrate the behavior of the solutions.

6 0
3 years ago
James rolls a number cube, with sides labeled 1 through 6, two times. What is the probability James will roll an even number the
charle [14.2K]

Answer:

1/6

Step-by-step explanation:

4 0
3 years ago
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