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3 years ago

Which of the following functions represent exponential decay?

Mathematics

1 answer:

Nuetrik [128]3 years ago

7 0

An exponential decay function goes down to the right, like in the picture attached.

An exponential function follows this format: $y=ab^x$ , where b is less than 1 and more than 0. b is more than 0 but less than 1 in function A.

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Find the surface area- and show ur work pls

solong [7]

Answer:

240

Step-by-step explanation:

8 0

3 years ago

Jimmy cell phone plan has been a base charge of $50 per month with an additional charge of 65 cents per app downloaded. Lisa cel

Soloha48 [4]

Answer:

Step-by-step explanation:

We write what we know.

Jimmy

$50/mo app 65¢ or .65

Lisa

$55/mo app 40¢ or .40

a = number of apps

The difference will come from the number of apps, a.

We need them to equal each other so let's write an equation.

$50 + .65a = $55 + .40a

We need to solve for a.

$50 + .65a = $55 + .40a subtract $50 for each side.

$50 - $50 + .65a = $55 - $50 + .40a

.65a = $55 - $50 + .40a

.65a = $5 + .40a subtract .40a from each side

.65a - .40a = $5 + .40a - .40a

.65a - .40a = $5

.25a = $5 Divide each side by .25

.25a/.25 = $5/.25

a = $5/.25

a = 20

So Jimmy and Lisa need to download 20 apps for their bill to be the same.

7 0

3 years ago

21 = − 6 x − 3 x + 4 + 4 x

horsena [70]

Answer:

x=-17/5

Step-by-step explanation:

1. Simplify -6x-3x+4+4x−6x−3x+4+4x to -5x+4−5x+4.

21=−5x+4

2. Subtract 44 from both sides.

21−4=−5x

3. Simplify 21-4 to 17.

17=-5x

4. Divided both sides by -5.

-17/5=x

5. Switch sides.

x=-17/5

Hope this helps.

4 0

3 years ago

A survey of 14 middle school students showed the mean number of minutes students talked on the cell phone in a week was 133. Wha

Orlov [11]

Roughly 1862 minutes.

4 0

3 years ago

Let t(x) = 3x-8 and s(t(x)) = x^2 + 3x - 2. Find s(1).

ratelena [41]

<h3>Answer: 16</h3>

=============================================================

Explanation:

Equate s(t(x)) and s(1) to find that t(x) = 1 must be the case.

Let's find what x must be.

t(x) = 3x-8

1 = 3x-8

1+8 = 3x

9 = 3x

3x = 9

x = 9/3

x = 3

So plugging x = 3 into t(x) gets us t(x) = 1

In other words, t(3) = 1

So that tells us s(t(3)) = s(1)

-------------

Let's plug x = 3 into the s(t(x)) equation

s(t(x)) = x^2 + 3x - 2

s(t(3)) = (3)^2 + 3(3) - 2

s(1) = 9 + 3(3) - 2

s(1) = 9 + 9 - 2

s(1) = 18 - 2

s(1) = 16

7 0

3 years ago