I’m not sure if this was a typo, but A and B are the same answer. A and B are correct, because when you solve this the answer has to be anything less than -0.6.
Answer:
x = 5/39
, y = 539/39
Step-by-step explanation:
Solve the following system:
{y - 2.5 x = 13.5
12.25 x - y = -12.25
In the first equation, look to solve for y:
{y - 2.5 x = 13.5
12.25 x - y = -12.25
y - 2.5 x = y - (5 x)/2 and 13.5 = 27/2:
y - (5 x)/2 = 27/2
Add (5 x)/2 to both sides:
{y = 1/2 (5 x + 27)
12.25 x - y = -12.25
Substitute y = 1/2 (5 x + 27) into the second equation:
{y = 1/2 (5 x + 27)
1/2 (-5 x - 27) + 12.25 x = -12.25
(-5 x - 27)/2 + 12.25 x = 12.25 x + (-(5 x)/2 - 27/2) = 9.75 x - 27/2:
{y = 1/2 (5 x + 27)
9.75 x - 27/2 = -12.25
In the second equation, look to solve for x:
{y = 1/2 (5 x + 27)
9.75 x - 27/2 = -12.25
9.75 x - 27/2 = (39 x)/4 - 27/2 and -12.25 = -49/4:
(39 x)/4 - 27/2 = -49/4
Add 27/2 to both sides:
{y = 1/2 (5 x + 27)
(39 x)/4 = 5/4
Multiply both sides by 4/39:
{y = 1/2 (5 x + 27)
x = 5/39
Substitute x = 5/39 into the first equation:
{y = 539/39
x = 5/39
Collect results in alphabetical order:
Answer: {x = 5/39
, y = 539/39
For me, this is a strange question...
Any two circles are similar.
Step-by-step explanation:
<em>When two figures are similar, they have the same shape, and the ratios of the lengths of their corresponding sides (segments) are equal.</em>
Two circles have the same shape.
The radiuses are corresponding segments and the diameters are corresponding segments. The ratio of lengths radiuses and diameters are equal.
If you want calculate it, then.
Circle A: r₁ = 5, d₁ = (2)(5) = 10
Circle B: r₂ = 15, d₂ = (2)(15) = 30
r₂/r₁ = 15/5 = 3
d₂/d₁ = 30/10 = 3
r₂/r₁ = d₂/d₁
Hi there!
Since we have a right-angled triangle, we can use the Pythagorean Theorem to find our answer. The Pythagorean Theorem states the following:
In this formula a and b represent the legs of the triangle and c represents the length of the hypotenuse.
Let's substitute our data from the question.
Square.
Add.
And finally take the root of both sides. We only need to use the positive solution, since the length of the hypotenuse can't be negative.
The answer is B.
