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asambeis [7]
3 years ago
7

The roots of the equation x^3+ax^2+bx+c=0 are 1,3 and 3. Show that c= -9 and find the value of a and of b.

Mathematics
1 answer:
KonstantinChe [14]3 years ago
4 0

Answer:

If the equation's roots are 1 , 3, 3 then the equation can be formed by multiplying

(x -1) * ( x - 3) * (x-3) =0

x^2 -6x + 9 * (x -1) equals

x^3 -6x^2 +9x -x^2 + 6x -9 = 0 equals

x^3 -7x^2 + 15x  -9 = 0

cubic equations GENERALLY have the form

ax^3 +bx^2 + cx +d = 0

Therefore

a =1  b = -7  c = 15 and d = -9

So, to make the numbers equal the equation in the problem:

x^3 + ax^2 + bx + c = 0

a = -7 b = 15 and c = -9

Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Write and solve a system of equations. Be sure to label the variables. The sum of two numbers is twelve. Two times the first num
adoni [48]

The solution to the system of equations is x = 8, y = 4.

<h3>How to write the system of equations?</h3>

First, let's define our variables as x and y.

"the sum of two numbers is twelve" is written as:

x + y = 12

"two times the first number minus three times the second number is four" is written as:

2x - 3y = 4

Then the system of equations is:

x + y  = 12

2x - 3y = 4

<h3>How to solve it?</h3>

First, we isolate one of the variables in one equation, I will isolate x on the first one to get:

x = 12 - y

Now we replace this on the other equation, so we get:

2*(12 - y) - 3y = 4

Now we can solve this for y.

24 - 2y - 3y = 4

24 - 5y = 4

24 - 4 = 5y

20/5 = y = 4

Now we know the value of y, and:

x = 12 - y = 12 - 4 = 8

Then the solution of the system is:

x = 8, y = 4.

If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

7 0
2 years ago
Y
aev [14]

Answer:

See attachment.

a)  y = -x + 2

b)  (2,1)

Step-by-step explanation:

Explained in the attachment.

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