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ArbitrLikvidat [17]
3 years ago
15

Select ALL the correct answers.

Mathematics
2 answers:
swat323 years ago
7 0
5.2 x 10-2 and 5.2 x 10-1
oee [108]3 years ago
6 0

Answer:5.2 x 10-1

Step-by-step explanation:hope i could help ;)

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Need the help asp!!!
Bond [772]

Answer:

It would be 8

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
I need to find the area of the shaded region, but I need detailed steps
olasank [31]
The shaded region is a parallelogram.

The formula for the area of any parallelogram is A=bh.

The base of the parallelogram is 2 meters long (given).

The height of the parallelogram is 9 meters (do not be fooled by the unnecessary information of 14 meters)
The height is 9 meters because the height has to be perpendicular to the base. Thus, the side length must be 9 meters.

Multiply them together.

2 \times 9 = 18

The area of the parallelogram is 18 square meters.
7 0
3 years ago
Sara spent half of her allowance going to the movies. She washed the family car and earned 9 dollars. What is her weekly allowan
Genrish500 [490]
$7, I think. I would not be too sure about it, though.
3 0
3 years ago
Read 2 more answers
You roll a pair of honest dice. If you roll a total of 7, you win $18; if you roll a total of 11, you win $54; if you roll any o
amm1812
Answer: -1
The negative value indicates a loss

============================================================

Explanation:

Define the three events
A = rolling a 7
B = rolling an 11
C = roll any other total (don't roll 7, don't roll 11)

There are 6 ways to roll a 7. They are
1+6 = 7
2+5 = 7
3+4 = 7
4+3 = 7
5+2 = 7
6+1 = 7
Use this to compute the probability of rolling a 7
P(A) = (number of ways to roll 7)/(number total rolls) = 6/36 = 1/6
Note: the 36 comes from 6*6 = 36 since there are 6 sides per die

There are only 2 ways to roll an 11. Those 2 ways are:
5+6 = 11
6+5 = 11
The probability for event B is P(B) = 2/36 = 1/18

Since there are 6 ways to roll a "7" and 2 ways to roll "11", there are 6+2 = 8 ways to roll either event. 
This leaves 36-8 = 28 ways to roll anything else
P(C) = 28/36 = 7/9

-----------------------------

In summary so far,
P(A) = 1/6
P(B) = 1/18
P(C) = 7/9

The winnings for each event, let's call it W(X), represents the prize amounts.
Any losses are negative values
W(A) = amount of winnings if event A happens 
W(B) = amount of winnings if event B happens
W(C) = amount of winnings if event C happens
W(A) = 18
W(B) = 54
W(C) = -9

Multiply the probability P(X) values with the corresponding W(X) values
P(A)*W(A) = (1/6)*(18) = 3
P(B)*W(B) = (1/18)*(54) = 3
P(C)*W(C) = (7/9)*(-9) = -7

Add up those results
3+3+(-7) = -1

The expected value for this game is -1.
The player is expected to lose on average 1 dollar per game played.


Note: because the expected value is not 0, this is not a fair game.


7 0
3 years ago
Read 2 more answers
Find the product. (a^3b)^2 • 4ab3
elena-14-01-66 [18.8K]
(a^3b)^2 • 4ab^3
a^6b • 4ab^3
4a^6b+1b^3
6 0
3 years ago
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