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oksian1 [2.3K]
3 years ago
6

20 points. Help. No links. Ty :)

Mathematics
1 answer:
Andrej [43]3 years ago
6 0

\huge\boxed{Answer\hookleftarrow}

334

\huge\boxed{Explanation\hookleftarrow}

10 × 4 × 7 = 280

3 × 3 × 6 = 54

280 + 54 = 334

\huge\boxed{Mark -Brainliest\hookleftarrow}

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3(x−0.2)=1.8+x find x
bonufazy [111]

Answer:

x=6/5

Step-by-step explanation:

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What is 0.04 km, 420 cm, 4,600 mm, and 4.3 meters in order from least to greatest
Paul [167]

Answer:

420 cm, 4.3 meters, 4600 mm, 0.04 km

Step-by-step explanation:

We can solve this by converting each to the same unit. I will be using meters.

0.04 km

1 km = 1000 meters

1000 meters / 1 km = 1

multiply 0.04 km by 1 = 1000 meters / 1 km , keeping the km at the bottom to cross out

0.04 km * 1000 meters / 1 km = 40 meters

420 cm

100 cm = 1 meter

1 meter / 100 cm = 1

multiply 420 cm by this, keeping cm at the bottom so it crosses out

420 cm * 1 meter / 100 cm = 4.2 meters

4600 mm

1000 mm = 1 meter

1 meter / 1000 mm = 1

4600 mm * 1 meter / 1000 mm = 4.6 meters

Therefore, our order is

420 cm, 4.3 meters, 4600 mm, 0.04 km

6 0
2 years ago
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Blababa [14]

Answer:

2,000

4,000

7,000

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Step-by-step explanation:

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1 year ago
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An environmentalist wants to find out the fraction of oil tankers that have spills each month. Step 2 of 2 : Suppose a sample of
rewona [7]

Answer:

The 80% confidence interval for the population proportion of oil tankers that have spills each month is (0.199, 0.257).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Suppose a sample of 333 tankers is drawn. Of these ships, 257 did not have spills.

333 - 257 = 76 have spills.

This means that n = 333, \pi = \frac{76}{333} = 0.228

80% confidence level

So \alpha = 0.2, z is the value of Z that has a pvalue of 1 - \frac{0.2}{2} = 0.9, so Z = 1.28.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.228 - 1.28\sqrt{\frac{0.228*0.772}{333}} = 0.199

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.228 + 1.28\sqrt{\frac{0.228*0.772}{333}} = 0.257

The 80% confidence interval for the population proportion of oil tankers that have spills each month is (0.199, 0.257).

6 0
3 years ago
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