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Rom4ik [11]
3 years ago
10

The question and the answers choices are in the picture please and thank you :)

Mathematics
1 answer:
joja [24]3 years ago
8 0

Answer:

Option 3

Step-by-step explanation:

Hope this helps

Have a great day!

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In factored form please help
Brilliant_brown [7]

Answer:

3rd option

Step-by-step explanation:

\frac{3x^2-3}{x^2-5x+4} ( factorise numerator and denominator )

3x² - 3 ← factor out 3 from each term

= 3(x² - 1²) ← x² - 1 is a difference of squares and factors in general as

a² - b² = (a - b)(a + b)

x² - 1

= x² - 1²

= (x - 1)(x + 1) , then

3x² - 3 = 3²(x - 1)(x + 1) ← in factored form

--------------------------------

x² - 5x + 4

consider the factors of the constant term (+ 4) which sum to give the coefficient of the x- term (- 5)

the factors are - 1 and - 4 , since

- 1 × - 4 = + 4 and - 1 - 4 = - 5 , then

x² - 5x + 4 = (x - 1)(x - 4)

then

\frac{3x^2-3}{x^2-5x+4} = \frac{3(x-1)(x+1)}{(x-1)(x-4)} ← in factored form

3 0
2 years ago
You earn $102 for doing 12 hours of yard work. Your friend earns $120 working at a store for 15 hours.
krek1111 [17]

Answer:

You earn more per hour and you would get $127.50

Step-by-step explanation:

You can find how much money you get per hour by dividing! 102 divided by 12 is 8.5 and 120 divided by 15 is 8 so you get more!

3 0
2 years ago
• Solve using the quadratic formula<br> 2x2 + 11x +15= 0
artcher [175]

Answer:

x=-5/2, -3

Step-by-step explanation:

2x^2+11x+15=0

factor out the trinomial

(2x+5)(x+3)=0

zero property,

2x+5=0, x+3=0

2x=0-5=-5, x=-5/2

x=0-3=-3

3 0
3 years ago
Harry drew the number line below to solve a word problem
Oduvanchick [21]
Where’s the answer choices??? the picture?? did you finish the question??
5 0
3 years ago
Find the distance between the two points. Round your solution to 2 decimal points.
VashaNatasha [74]
Notice the grid, the points are (-5, -2) and (4, -1), thus

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~{{ 4}} &,&{{ -1}}~) &#10;%  (c,d)&#10;&&(~{{ -5}} &,&{{ -2}}~)&#10;\end{array}~~&#10;%  distance value&#10;d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}&#10;\\\\\\&#10;d=\sqrt{[-5-4]^2+[-2-(-1)]^2}\implies d=\sqrt{(-5-4)^2+(-2+1)^2}&#10;\\\\\\&#10;d=\sqrt{(-9)^2+(-1)^2}\implies d=\sqrt{81+1}\implies d=\sqrt{82}
6 0
3 years ago
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