The equation of the perpendicular line is 13y=27-x
Step-by-step explanation:
Writing the given equation to slope-intercept form.
y=− 1 3 x+6
The slope of this line is 13
The perpendicular slope is -1/13
Using the new slope and the given point into the slope-intercept form to find the y-intercept.
4=-1/13(2)+c
2=-1/13+c
c=27/13
y=-1/13x+27/13
So the equation of the perpendicular line is 13y=27-x
Answer:
-37
Step-by-step explanation:
1) to find the equation of the given line (its slop-interception form is y=mx+i, where m - slop, i - interception):
a) y=2x+i, where m=2;
b) it is possible to calculate the value of 'i' after the substitution the point (5;-3) into the equation y=2x+i:
-3=2*5+i; ⇒ i= -13;
c) the equation of the given line is y=2x-13.
2) to calculate the value of 'R':
if to substitute the point (-12;R) into the equation y=2x-13, then
R=2*(-12)-13; ⇒ R= -37.
If it's absolute value, then it is 1.1
Just the positive number.
Answer:
Hi,
Step-by-step explanation:
Using the pythagorean theorem , let's calculate the apothem of a side:
a²=26²-10²=57=24²
Area of a side: 24*10*2/2=240 (ft²)
Lateral area=240*4=960(ft²)
Area of the base: 20²=400 (ft²)
Total area=1360(ft²)
