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Andrew [12]
3 years ago
12

A gas is at 39.2c and 4.50L. What is the temperature (oC) when the gas is expanded to 10L?

Chemistry
1 answer:
viva [34]3 years ago
3 0

Answer:

420.7 degrees C

Explanation:

Use the formula V1/T1 = V2/T2 (Charles' Law) to find T2. Make sure to convert  your temperatures to Kelvin by adding 273 to the Celsius temperature.

V1 = 4.50 L

V2 = 10 L

T1 = 39.2 C = 312.2 K

Solve V1/T1 = V2/T2 for T2 and you get T2 = V2T1/V1

T2 = (10 L)(312.2 K) / (4.50 L) = 693.8 K

You can subtract 273 to get the temperature back to Celsius.

T2 = 693.8 - 273 = 420.7 degrees C

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a gas that exerts a pressure of 215 torr in a container with a volume of 51.0 mL will exert a pressure of ? torr when transferre
zhannawk [14.2K]
To calculate the new pressure, we can use Boyle’s law to relate these two scenarios (Boyle’s law is used because the temperature is assumed to remain constant). Boyle’s law is:

P1V1 = P2V2,

Where “P” is pressure and “V” is volume. The pressure and volume of the first scenario is 215 torr and 51 mL, respectively, and the second scenario has a volume of 18.5 L (18,500 mL) and the unknown pressure - let’s call that “x”. Plugging these into the equation:

(215 torr)(51 mL) =(“x” torr)(18,500 mL)
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Hope this helps!
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If I add 475mL of water to 75.0mL of a 0.315M NaOH solution, what will the molarity of the diluted solution be?
pantera1 [17]
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shusha [124]
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mario62 [17]

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