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kolezko [41]
3 years ago
7

According to the law of conservation of energy,

Chemistry
1 answer:
qaws [65]3 years ago
6 0
I believe the answer is c
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During photosynthesis, what gas do plants release
ELEN [110]
During photosynthesis, what gas do plants release - oxygen
5 0
2 years ago
How many molecules of he are contained in a 10.0 l tank at 7.53 atm and 485 k?
ankoles [38]

Answer:

1.126 x 10^22

Explanation:

pV = nRT

7.53 x 10 = n x 8.31 x 485

n = (7.53 x 10) / (8.31 x 485) = 0.0187 moles

M = n x Avogadros number

0.0187 x 6.02 x 10^23 = 1.126 x 10^22

4 0
3 years ago
A 100 g sample of potassium chlorate, KCIO3(s), is completely decomposed by heating:
Mama L [17]
Explanation:
In order to be able to calculate the volume of oxygen gas produced by this reaction, you need to know the conditions for pressure and temperature.
Since no mention of those conditions was made, I'll assume that the reaction takes place at STP, Standard Temperature and Pressure.
STP conditions are defined as a pressure of
100 kPa
and a temperature of
0
∘
C
. Under these conditions for pressure and temperature, one mole of any ideal gas occupies
22.7 L
- this is known as the molar volume of a gas at STP.
So, in order to find the volume of oxygen gas at STP, you need to know how many moles of oxygen are produced by this reaction.
The balanced chemical equation for this decomposition reaction looks like this
2
KClO
3(s]
heat
×
−−−→
2
KCl
(s]
+
3
O
2(g]
↑
⏐
⏐
Notice that you have a
2
:
3
mole ratio between potassium chlorate and oxygen gas.
This tells you that the reaction will always produce
3
2
times more moles of oxygen gas than the number of moles of potassium chlorate that underwent decomposition.
Use potassium chlorate's molar mass to determine how many moles you have in that
231-g
sample
231
g
⋅
1 mole KClO
3
122.55
g
=
1.885 moles KClO
3
Use the aforementioned mole ratio to determine how many moles of oxygen would be produced from this many moles of potassium chlorate
1.885
moles KClO
3
⋅
3
moles O
2
2
moles KClO
3
=
2.8275 moles O
2
So, what volume would this many moles occupy at STP?
2.8275
moles
⋅
22.7 L
1
mol
=
64.2 L
6 0
3 years ago
2/10
emmainna [20.7K]

Answer:

pH=2.34

Explanation:

HBr  -> H  + Br

The dissociation it's complete, for that reason the concentration of the products is the same of HBr

[H+]=[Br-]=0.00234 M

pH= - log (0.00234)=2.34

6 0
3 years ago
How many grams of solute are needed to make 37.5 mL of 0.750 M KI solution? Round to three significant digits.
Marysya12 [62]

4.648 gm of solute is needed to make 37.5 mL of 0.750 M KI solution.

Solution:  

We will start with the Molarity  

\text { Molarity }=\text { Mole of solute } \div \text { liter of solution }

Also we know 1000 ml = 1 L

Therefore 37.5 ml by 1000ml we obtained 0.0375L  

Equation for solving mole of solute

\text { Mole of solute }=\text { Molarity } \times \text { Liters of solution }

Now, multiply 0.750M by 0.0375

Substitute the known values in the above equation we get

0.750 \times 0.0375=0.0281

Also we know that Molar mass of KI is 166 g/mol

So divide the molar mass value to get the no of grams.

0.028 \times 166=4.648

So 4.648 gm of Solute is required for make 37.5 mL of 0.750 M KI solution.

8 0
3 years ago
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