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strojnjashka [21]
2 years ago
9

Dose Anabolic Reaction helps cells multiply and stay good condition

Chemistry
1 answer:
Schach [20]2 years ago
3 0
Addison reaction the water is bubbles please don’t report me
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explain how both hydrogen and carbon have achieved stability by bonding with each other to form methane ​
Naya [18.7K]

A carbon iota can bond with four other iotas and is just like the four-hole wheel, whereas an oxygen iota, which can bond only to two, is just like the two-hole wheel.

4 0
2 years ago
Read 2 more answers
This reaction type occurs when different atoms in two different compounds trade places.
Scorpion4ik [409]
Your answer would be D, single replacement
3 0
3 years ago
Cal is titrating 50.8 mL of 0.319 M HBr with 0.337 M Ba(OH)2. How many mL of Ba(OH)2 does Cal need to add to reach the equivalen
alexgriva [62]

Answer:

V_{base}=24.04mL

Explanation:

Hello!

In this case, according to the chemical reaction by which HBr reacts with Ba(OH)2:

2HBr+Ba(OH)_2\rightarrow BaBr_2+2H_2O

We can see there is a 2:1 mole ratio between the acid and the base; thus, at the equivalent point we can write:

2M_{base}V_{base}=M_{acid}V_{acid}

Therefore, for is to compute the volume of the used base, we proceed as shown below:

V_{base}=\frac{M_{acid}V_{acid}}{2M_{base}}

And we plug in to obtain:

V_{base}=\frac{0.319M*50.8mL}{2*0.337M}\\\\V_{base}=24.04mL

Best regards!

8 0
3 years ago
A beaker contains a mixture of sand and small pebbles. what kind of mixture is this?
melomori [17]
Answer is: a beaker contains <span>heterogeneous mixture.

</span>

A heterogeneous mixture<span> have compounds that remain separate in the sample.</span>

Heterogeneous mixture is not uniform in composition (in this mixture different sand and small pebbles), but proportions of its components (in this mixture particles of different colors and size) vary throughout the sample.

3 0
3 years ago
3 The volume of a gas is 50.0 mL at 20.0 K. What will be the new
Damm [24]

Answer:

C. 4.00 K

Explanation:

We can solve this using Charles's Law of the ideal gas. The law describes that when the pressure is constant, the volume will be directly proportional to the temperature. Note that the temperature here should only use the Kelvin unit. Before compressed, the volume of the gas is 50ml(V1) and the temperature is 20K (T1). After compressed the volume becomes 10ml(V2). The calculation will be:

V1 / T1= V2 / T2

50ml / 20K = 10ml / T2

T2= 10ml/ 50ml * 20K

T2= 4K

7 0
3 years ago
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