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Maslowich
2 years ago
7

Write the first five terms of each sequence.

Mathematics
1 answer:
AleksandrR [38]2 years ago
4 0

Answer:

...

Step-by-step explanation:

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Which number is in the solution set of this equation? 7x − 9 = 40
skad [1K]

Answer: the answer is 7

Step-by-step explanation: add 9 to both sides, eliminating -9 so now you have 7x=49 divide both by 7 and you get x= 7 check it by inputing 7 for x, 7(7)-9=40

7(7)=49 next 49-9= 40

it checks out, so x= 7

7 0
3 years ago
Melinda has shown that a function, f(x), increases by 4 for every unit in the domain. What does this prove?
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It proves The function f(x) is an arithmetic sequence.
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What is 1/2b^2-b in factored form ?
slega [8]
B(1/2b-1)................


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2 years ago
Which is defined using the undefined terms point and line
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It's a ray because it has a point and one line that goes on in a direction.

Step-by-step explanation:

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2 years ago
Is x+y+1=0 a tangent of both y^2=4x and x^2=4y parabolas?
Lubov Fominskaja [6]

Answer:

  yes

Step-by-step explanation:

The line intersects each parabola in one point, so is tangent to both.

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For the first parabola, the point of intersection is ...

  y^2 = 4(-y-1)

  y^2 +4y +4 = 0

  (y+2)^2 = 0

  y = -2 . . . . . . . . one solution only

  x = -(-2)-1 = 1

The point of intersection is (1, -2).

__

For the second parabola, the equation is the same, but with x and y interchanged:

  x^2 = 4(-x-1)

  (x +2)^2 = 0

  x = -2, y = 1 . . . . . one point of intersection only

___

If the line is not parallel to the axis of symmetry, it is tangent if there is only one point of intersection. Here the line x+y+1=0 is tangent to both y^2=4x and x^2=4y.

_____

Another way to consider this is to look at the two parabolas as mirror images of each other across the line y=x. The given line is perpendicular to that line of reflection, so if it is tangent to one parabola, it is tangent to both.

7 0
3 years ago
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