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Len [333]
3 years ago
14

Factor this polynomial expression.

Mathematics
2 answers:
Lapatulllka [165]3 years ago
8 0

Answer:

The answer is A

Step-by-step explanation:

I'm good at factoring lol

Elan Coil [88]3 years ago
7 0

Answer:

Step-by-step explanation:

(3x+2)( 5x−4)

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When Lily does a self-inventory, she lists her knowledge of Excel, her proficiency in bookkeeping, and her training in customer
Anika [276]

Answer:

The above mentioned qualities go under the category of abilities.

Step-by-step explanation:

Lily does a self-inventory to find out theat she has knowledge of Excel , proficiency in bookkeeping and training in customer service .

Ability is used to refer a person's native aptitude in a specific field.

Ability can also be trained and honed and can be made better with practice.

All of Lily's qualities mentioned come under the same above mentioned specifications. All her talents can be trained and can be bettered.

Hence her qualities come under the category of abilities.

6 0
3 years ago
Convert 0.0001 to a power of 10.
Damm [24]
<span> 10^-4 is the answer</span>
4 0
3 years ago
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The speed limit on a highway is 60 mph write and graph an inequality that describes the situation
kirza4 [7]
<span>speed limit < = 60
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3 0
3 years ago
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Michelle has 21 ⅙ cups of flour in a container. She uses 6 ⅚ cups of flour to make 5 loaves of bread. How much flour does Michel
Bezzdna [24]
It should be about -13 cups
7 0
3 years ago
Evaluate using <br> Definite integrals
swat32

Since [0,4]=[0,1]\cup(1,4], we can rewrite the integral as

\displaystyle \int_0^1f(t)\;dt + \int_1^4 f(t)\; dt

Now there is no ambiguity about the definition of f(t), because in each integral we are integrating a single part of its piecewise definition:

\displaystyle \int_0^1f(t)\;dt = \int_0^11-3t^2\;dt,\quad \int_1^4 f(t)\; dt = \int_1^4 2t\; dt

Both integrals are quite immediate: you only need to use the power rule

\displaystyle \int x^n\;dx=\dfrac{x^{n+1}}{n+1}

to get

\displaystyle \int_0^11-3t^2\;dt = \left[t-t^3\right]_0^1,\quad \int_1^4 2t\; dt = \left[t^2\right]_1^4

Now we only need to evaluate the antiderivatives:

\left[t-t^3\right]_0^1 = 1-1^3=0,\quad \left[t^2\right]_1^4 = 4^2-1^2=15

So, the final answer is 15.

4 0
4 years ago
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