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3 years ago

7

Keiko sold t-shirts at a festival. She made $4 for each t-shirt she sold. Her expenses were $25. If she made a profit of $71, ho

w many t-shirts did she sell?

2 answers:

ehidna [41]3 years ago

7 0

Answer:

She had sold 24 shirts.

Gnom [1K]3 years ago

4 0

Answer:

24 shirts.

Step-by-step explanation:

Let the number of shirt she sold = x.

4x - 25 = 71

4x = 96

x = 24.

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The question is in the photo. it is asking for 2 answers

Alex777 [14]

9514 1404 393

Answer:

2nd force: 99.91 lb
resultant: 213.97 lb

Step-by-step explanation:

In the parallelogram shown, angle B is the supplement of angle DAB:

∠B = 180° -77°37' = 102°23'

Angle ACB is the difference of angles 77°37' and 27°8', so is 50°29'.

Now, we know the angles and one side of triangle ABC. We can use the law of sines to solve for the other two sides.

BC/sin(A) = AB/sin(C)

AD = BC = AB·sin(A)/sin(C) = (169 lb)sin(27°8')/sin(50°29') ≈ 99.91 lb

AC = AB·sin(B)/sin(C) = (169 lb)sin(102°23')/sin(50°29') ≈ 213.97 lb

7 0

3 years ago

There are 35 more musicians in the String section of a city Symphony Orchestra than in its Brass section. There are 29 musicians

blagie [28]

X = string section
y = brass section

x = y + 35
y = 29 .....there are 29 in the brass section

x = 29 + 35
x = 64...there are 64 in the string section

for a total of : 64 + 29 = 93 total musicians <==

3 0

3 years ago

What exactly does skew mean?

Sever21 [200]

Two parallel lines are skew if they are not parallel but are in different planes, which means that they will not intersect, in spite of they are not parallel.

7 0

3 years ago

Carter's mom has ¼ of a pan of brownies leftover. If Carter and two of his friends share the leftover brownies equally, what fra

antoniya [11.8K]

Answer:

x/12

Step-by-step explanation:

1/4 of a pan of brownies leftover.

=1/4 of x

=1/4*x

=x/4

If Carter and two of his friends shares the leftover=3 people

Each friend will get

x/4÷3

=x/4×1/3

=x/12

3 0

3 years ago

Law of radicals

andrey2020 [161]

Answer:

1) $\sqrt{x^7}=x^{\frac{7}{2}$

2) $\sqrt[3]{y^5}=y^{\frac{5}{3}$

3) $\sqrt[5]{a^{12}}=a^{\frac{12}{5} }$

4) $\sqrt[4]{z^{9}}=z^\frac{9}{4}$

Step-by-step explanation:

1) $\sqrt{x^7}$

We know that $\sqrt{x}=x^{\frac{1}{2}$

So, $\sqrt{x^7}=x^{\frac{7}{2}$

2) $\sqrt[3]{y^5}$

We know that $\sqrt[3]{x}=x^{\frac{1}{3}$

So, $\sqrt[3]{y^5}=y^{\frac{5}{3}$

3) $\sqrt[5]{a^{12}}$

We know that $\sqrt[5]{x}=x^{\frac{1}{5}$

So, $\sqrt[5]{a^{12}}=a^{\frac{12}{5} }$

4) $\sqrt[4]{z^{9}}$

We know that $\sqrt[4]{x}=x^{\frac{1}{4}$

So, $\sqrt[4]{z^{9}}=z^\frac{9}{4}$

6 0

3 years ago