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3 years ago

7

Keiko sold t-shirts at a festival. She made $4 for each t-shirt she sold. Her expenses were $25. If she made a profit of $71, ho

w many t-shirts did she sell?

2 answers:

ehidna [41]3 years ago

7 0

Answer:

She had sold 24 shirts.

Gnom [1K]3 years ago

4 0

Answer:

24 shirts.

Step-by-step explanation:

Let the number of shirt she sold = x.

4x - 25 = 71

4x = 96

x = 24.

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slega [8]

Answer: The range of the function is all real numbers less than or equal to 9

Step-by-step explanation:

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2 years ago

Ruth has 6 chores to do. If each chore does not depend on the others, in how many different orders could she do the chores?

Mice21 [21]

First chore, 6 to choose from.
Second chore, 5 to choose from.
Third chore, 4 to choose from.
Fourth chore, 3 to choose from.
Fifth chore, 2 to choose from.
Sixth chore, 1 to "choose" from.
The total number of orders possible is the product
6*5*4*3*2*1=6!=720

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3 years ago

Read 2 more answers

What is the slope of the line through -1,-7 and 3,9

Lelechka [254]

Answer:

The slope is 4

Step-by-step explanation:

You can find the point by doing

9+7

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3+1

which equals 16/4 = 4

the slope is 4

5 0

3 years ago

Read 2 more answers

3. List all the coefficients and constants

7nadin3 [17]

The coefficient is 4
The constants are 2 and 3

5 0

3 years ago

et f(x) = x + |2x − 3|. Find all solutions to the equation f(x) = 12. (Enter your answers as a comma-separated list. If an answe

Alinara [238K]

Answer:

1. {5,-9}

2.{4}

3.{9/2}

Step-by-step explanation:

The equation $f(x)=x+\lvert 2x-3 \rvert=12$ can be solved as follows:

$x+\lvert 2x-3 \rvert =12\,\,\,\text{(given equation)}$

$\lvert 2x-3 \rvert =12-x$

$2x-3=12-x\,\,\text{or}\,\,2x-3=-(12-x)$

$3x=15\,\,\text{or}\,\,\x=-9$

Then, the solutions of the equation are $x=5, x=-9$ .

Now, if $g(x)=5x-3+\lvert x+4\rvert$ , we can solve the equation $g(a)=4a+9$ as follows:

$5a-3+\lvert a+4 \rvert =4a+9$

$\lvert a+4\rvert =4a+9-5a+3$

$a+4 =-a+12\,\,\text{or}\,\,a+4=-(-a+12)$

$2a=8\,\,\text{or}\,\,4=12$

So, the unique solution of this last equation is $a=4$

The last equation is $h(x-1)=x-3$ , where $h(x)=\lvert x \rvert -2x+5.$ . To solve this equation we can proceed as follows:

$h(x-1)=x-3$

$\lvert x-1\rvert -2(x-1)+5=x-3$

$\lvert x-1 \rvert -2x+2+5=x-3$

$\lvert x-1\rvert =3x-10$

$x-1=3x-10\,\,\text{or}\,\,x-1=-(3x-10)$

$-2x=-9\,\,\text{or}\,\,4x=11$

$x=9/2\,\,\text{or}\,\,x=11/4$

But, x=11/4 is not a solution of this equation. So the unique solution is x=9/2.

8 0

3 years ago