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AnnZ [28]
3 years ago
12

What unit system of measurement does F represent

Mathematics
1 answer:
earnstyle [38]3 years ago
4 0

Answer:

Fahrenheit

Unit system Imperial/US customary

Unit of Temperature

Symbol °F

Named after Daniel Gabriel Fahrenheit

Step-by-step explanation:

hope it helps

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I need help answering this one
Montano1993 [528]

Answer:

9 units

Step-by-step explanation:

when 0 acts as center ; the circle is 9 units form the centerfrom the graph

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plzz mark me brainliest

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3 years ago
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Please hurry... A boat traveled 36 miles in 3 hours.At this rate,how many miles will the boat travel in 0.5 hour. This is not a
Nataly [62]

velocity of the boat = 36miles/3 hours

divide denominator and numerator by 6 respectively

6 miles/0.5hrs

thus, the we can say that the boat will travel 6 miles in 0.5 hour

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3 years ago
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LINEAR ALGEBRA
kenny6666 [7]

Answer:

The value of the constant k so that \vec u_{3} is a linear combination of \vec u_{1} and \vec u_{2} is \frac{7}{10}.

Step-by-step explanation:

Let be \vec u_{1} = [2,3,1], \vec u_{2} = [4,1,0] and \vec u_{3} = [1, 2,k], \vec u_{3} is a linear combination of \vec u_{1} and \vec u_{3} if and only if:

\alpha_{1} \cdot \vec u_{1} + \alpha_{2} \cdot \vec u_{2} +\alpha_{3}\cdot \vec u_{3} = \vec O (Eq. 1)

Where:

\alpha_{1}, \alpha_{2}, \alpha_{3} - Scalar coefficients of linear combination, dimensionless.

By dividing each term by \alpha_{3}:

\lambda_{1}\cdot \vec u_{1} + \lambda_{2}\cdot \vec u_{3} = -\vec u_{3}

\vec u_{3}=-\lambda_{1}\cdot \vec u_{1}-\lambda_{2}\cdot \vec u_{2} (Eq. 2)

\vec O - Zero vector, dimensionless.

And all vectors are linearly independent, meaning that at least one coefficient must be different from zero. Now we expand (Eq. 2) by direct substitution and simplify the resulting expression:

[1,2,k] = -\lambda_{1}\cdot [2,3,1]-\lambda_{2}\cdot [4,1,0]

[1,2,k] = [-2\cdot\lambda_{1},-3\cdot \lambda_{1},-\lambda_{1}]+[-4\cdot \lambda_{2},-\lambda_{2},0]

[0,0,0] = [-2\cdot \lambda_{1},-3\cdot \lambda_{1},-\lambda_{1}]+[-4\cdot \lambda_{2},-\lambda_{2},0]+[-1,-2,-k]

[-2\cdot \lambda_{1}-4\cdot \lambda_{2}-1,-3\cdot \lambda_{1}-\lambda_{2}-2,-\lambda_{1}-k] =[0,0,0]

The following system of linear equations is obtained:

-2\cdot \lambda_{1}-4\cdot \lambda_{2}= 1 (Eq. 3)

-3\cdot \lambda_{1}-\lambda_{2}= 2 (Eq. 4)

-\lambda_{1}-k = 0 (Eq. 5)

The solution of this system is:

\lambda_{1} = -\frac{7}{10}, \lambda_{2} = \frac{1}{10}, k = \frac{7}{10}

The value of the constant k so that \vec u_{3} is a linear combination of \vec u_{1} and \vec u_{2} is \frac{7}{10}.

4 0
4 years ago
Factor the algebraic expression: 28a + 12
Vladimir [108]

Answer:

hope it is helpful to you

3 0
3 years ago
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A bank account grows by 7% each year .by what percentage dose it grow each decade
Zinaida [17]

Answer:

Each decade it grows by 10% because a whole decade is 10 years

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3 years ago
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