F(2-k)=8-5(2-k) pls help me lol

Mathematics

2 answers:

slavikrds [6]3 years ago

7 0

Answer:

Step-by-step explanation:

f= 5k-2/-k+2

fenix001 [56]3 years ago

4 0

Answer:

f= 5k-2/-k+2

Step-by-step explanation:

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PLEASE HELP I WILL BRAINLIST

PSYCHO15rus [73]

Answer:

Step-by-step explanation:

Since they intersect you can just solve for x and y

since y=-4x and y=x^2+2x+8, you can set -4x=x^2+2x+8

add 4x to both sides to make 0=x^2+6x+8

and factor out (x+4)(x+2)

so the solutions for x are -4 and -2

then insert the two values for x into the first equation

so y=-4(-4) and y=-4(-2)

so y=16 and y=8 when x=-4 and x=-2

so the smallest value for y in both equations is 8

Please give brainliest :)

3 0

3 years ago

Label the quadrants IV

nevsk [136]

Answer:

Quadrant IV is always in the bottom right corner.

8 0

2 years ago

The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean of 1262 and a s

Andrew [12]

Answer:

a) 1186

b) Between 1031 and 1493.

c) 160

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean of 1262 and a standard deviation of 118.

This means that $\mu = 1262, \sigma = 118$