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3 years ago

Help pls it has to be in an equation and ill mark brainliest.

Mathematics

1 answer:

Sonja [21]3 years ago

8 0

Answer:

y = 1/6x+2

Step-by-step explanation:

1/6=slope 2=y int. hope this kinda helps

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How do you solve 6-9(4p-3)= 2(6p+7)+3

Alika [10]

Answer:

p= 1/3

=0.333

Step-by-step explanation:

Simplifying

6 + -9(4p + -3) = 2(6p + 7) + 3

Reorder the terms:

6 + -9(-3 + 4p) = 2(6p + 7) + 3

6 + (-3 * -9 + 4p * -9) = 2(6p + 7) + 3

6 + (27 + -36p) = 2(6p + 7) + 3

Combine like terms: 6 + 27 = 33

33 + -36p = 2(6p + 7) + 3

Reorder the terms:

33 + -36p = 2(7 + 6p) + 3

33 + -36p = (7 * 2 + 6p * 2) + 3

33 + -36p = (14 + 12p) + 3

Reorder the terms:

33 + -36p = 14 + 3 + 12p

Combine like terms: 14 + 3 = 17

33 + -36p = 17 + 12p

Solving

33 + -36p = 17 + 12p

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '-12p' to each side of the equation.

33 + -36p + -12p = 17 + 12p + -12p

Combine like terms: -36p + -12p = -48p

33 + -48p = 17 + 12p + -12p

Combine like terms: 12p + -12p = 0

33 + -48p = 17 + 0

33 + -48p = 17

Add '-33' to each side of the equation.

33 + -33 + -48p = 17 + -33

Combine like terms: 33 + -33 = 0

0 + -48p = 17 + -33

-48p = 17 + -33

Combine like terms: 17 + -33 = -16

-48p = -16

Divide each side by '-48'.

p = 0.3333333333

Simplifying

p = 0.3333333333

3 0

3 years ago

Read 2 more answers

Differentiate the following functions (x^3+1)(x-2)÷x^2

Masja [62]

Given:

The given function is:

$\dfrac{(x^3+1)(x-2)}{x^2}$

To find:

The differentiation of the given function.

Solution:

Consider the given function,

$y=\dfrac{(x^3+1)(x-2)}{x^2}$

It can be written as:

$y=\dfrac{(x^3)(x)+(x^3)(-2)+(1)(x)+(1)(-2)}{x^2}$

$y=\dfrac{x^4-2x^3+x-2}{x^2}$

$y=\dfrac{x^4}{x^2}-\dfrac{2x^3}{x^2}+\dfrac{x}{x^2}-\dfrac{2}{x^2}$

$y=x^2-2x+\dfrac{1}{x}-\dfrac{2}{x^2}$

Differentiate with respect to x.

$y'=\dfrac{d}{dx}(x^2)-\dfrac{d}{dx}(2x)+\dfrac{d}{dx}(x^{-1})-\dfrac{d}{dx}\2(x^{-2})$

$y'=2x-2(1)+(-x^{-2})-2(-2x^{-3})$

$y'=2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$

Therefore, the differentiation of the given function is $2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$ .

8 0

3 years ago

A rectangle floor is 7 yards long and 4 yards wide. what is the area of the floor in square feet?

timofeeve [1]

Just multiply my friend

8 0

3 years ago

f(x) = −16x2 + 24x + 16 Part A: What are the x-intercepts of the graph of f(x)? Show your work. (2 points) WILL GIVE BRAINLIEST

castortr0y [4]

Answer:

Step-by-step explanation:

f(x) = −16x2 + 24x + 16 = 0 can be reduced to -2x^2 + 3x + 2 = 0 and then to 2x^2 - 3x - 2 = 0. Solve this for x using the quadratic formula:

The discriminant is b^2 - 4ac = (-3)^2 - 4(2)(-2) = 9 + 16 = 25.

Therefore the roots are:

-(-3) ± √25 3 ± 5

x = ----------------- = ------------ => x = 2 and x = -1/2

2(2) 4

The x-intercepts are points: (2, 0) and (-1/2, 0)

Because the coefficient of the x^2 term is negative, this graph opens down and the vertex represents a maximum.

To graph this function, find and plot the vertex. It is exactly halfway between the x-intercepts, that is, at x = 1 1/4, for which the y value is 21:

vertex and maximum at (5/4, 21)

Finally, find the y-intercept. Let x = 0; we find that y = 16. The y-intercept is 0, 16)

We now have four points on the graph and know where the maximum is. Plot this max (5/4, 21) and the x-intercepts (2, 0) and (-1/2, 0), and finally the y-intercept. Draw a smooth curve through these points, remembering that the graph is symmetrical about the axis of symmetry x = 5/4.

3 0

3 years ago

Using a calculator and the formula above, calculate the APR. Choose the correct answer.

GarryVolchara [31]

APR=(1+r/12)^(12)-1
APR=(1+0.16÷12)^(12)−1
APR=0.172×100
APR=17.2%

7 0

3 years ago

Help pls it has to be in an equation and ill mark brainliest.​

Help pls it has to be in an equation and ill mark brainliest.