Answer:
40
Step-by-step explanation:
i think? i may have not understood the picture correctly, so if this is wrong i apologise
Answer:
The inverse for log₂(x) + 2 is - log₂x + 2.
Step-by-step explanation:
Given that
f(x) = log₂(x) + 2
Now to find the inverse of any function we put we replace x by 1/x.
f(x) = log₂(x) + 2
f(1/x) =g(x)= log₂(1/x) + 2
As we know that
log₂(a/b) = log₂a - log₂b
g(x) = log₂1 - log₂x + 2
We know that log₂1 = 0
g(x) = 0 - log₂x + 2
g(x) = - log₂x + 2
So the inverse for log₂(x) + 2 is - log₂x + 2.
Answer:
Step-by-step explanation:
x = 3y.......(1)
x - 3y = 0 ....(2)
Substituting x in (1) into (2)
3y - 3y = 0
No solutions
Answer:
(x-6)^2
Step-by-step explanation:
