It would be 2*(5^2)
(2 multiply to (5 rise to the power of 2))
Hope that help.
Answer:
//The class called "Solution" is declared
public class Solution {
//Main method which signify the beginning of program execution
public static void main(String[] args) {
//myInt variable of type Integer is declared
Integer myInt;
// An object of type Integer is declared with initial value of 1
Integer newInt = new Integer(1);
// The value of the new declared and assigned object is displayed to the user
System.out.println(newInt);
// The new declared object is assigned to the reference variable myInt
myInt = newInt;
// The value of myInt is displayed to the user
System.out.println(myInt);
}
}
Step-by-step explanation:
the absolute value of the product of the zeros of a is 
.
<u>Step-by-step explanation:</u>
Here we have , 
is a polynomial function of t, where k is a constant. Given that a(2) = 0 . We need to find the absolute value of the product of the zeros of a . Let's find out:
Equation every factor of a(t) to zero we get:
⇒ 
⇒ 
⇒ 
But , t=2 So , 
. Now , the absolute value of the product of the zeros of a is :
⇒ 
⇒ 
⇒
Therefore, the absolute value of the product of the zeros of a is .
Answer:
Rope jumping, slow pace, < 100 skips/min, 2 foot skip, rhythm bounce 8.8 630
Rope jumping, moderate pace, 100-120 skips/min, general, 2 foot skip, plain bounce 11.8 845
Rope skipping, general 12.3 881
Rope jumping, fast pace, 120-160 skips/min 12.3 881
Step-by-step explanation:
