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NISA [10]
2 years ago
9

What is 314.16 rounded to the nearest hundredth

Mathematics
1 answer:
Galina-37 [17]2 years ago
4 0

Since there is no number in the thousandths place which would make the number in the hundredths place round up or down, we keep the number the same:

314.16

Hope it helps! Good luck. :)

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Select the correct answer from each drop down menu. In the figure, AB=__inches and AC=___
BaLLatris [955]

Answer: In the figure AB is about 8.4 inches and AC is about 13.05 inches.

Step-by-step explanation: We can use cosine to find the hypotenuse. cos(40)=\frac{10}{x} \\cos(40) (x)=\frac{10}{x}(x)\\cos(40) (x) =10\\\frac{cos(40) (x)}{cos (40)} =\frac{10}{cos (40)} \\x=\frac{10}{cos(40)}

Using a calculator x is about 13.05

Using tangent we can find the length opposite of <C

tan(40)=\frac{x}{10} \\tan(40) (10)=\frac{x}{10}(10)\\tan(40) (10) = x

Using a calculator x would be about 8.4

4 0
3 years ago
Read 2 more answers
the length of a rectangle is 4 more than 3 times the width. If the perimeter of the rectangle is 18.4cm, what is the area of the
antoniya [11.8K]

Answer:

A = 10.27cm²

Step-by-step explanation:

Let's represent the width as x,

therefore since the length is 4 more than 3 times the width, it can be represent as 3x + 4,   Perimeter = 18.4cm

Perimeter of a rectangle = 2(L + B)

18.4= 2(3x+4+x)\\18.4= 6x+8+2x\\18.4-8=6x+2x\\10.4=8x\\x=\frac{10.4}{8}\\x=1.3

width = 1.3cm

Length = 3x + 4 = 3*1.3 + 4 = 7.9cm

Area of a rectangle = length x width

A = 7.9 * 1.3 = 10.27cm²

6 0
2 years ago
Read 2 more answers
Write the result of subtracting the second equation from the first?
aksik [14]

Answer:

Could you please put a link to the question???

Step-by-step explanation:

We can only solve the question if you give us more info about the question.

8 0
3 years ago
Sixty seven percent of the employees in a company have managerial positions, and 58 percent of the employees in the company have
Kazeer [188]

Answer: The proportion of employees who either have MBAs or are managers are 0.58.

Step-by-step explanation:

Since we have given that

Probability of employees having managerial positions = 67%

Probability of employees having MBA degrees = 58%

Probability of managers having MBA degrees = 67%

So, using probability formulas, we get that

P(A\cup B)=P(A)+P(B)-P(A\cap B)\\\\P(A\cup B)=0.67+0.58-0.67\\\\P(A\cup B)=0.58

Hence, the proportion of employees who either have MBAs or are managers are 0.58.

7 0
3 years ago
The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.
Mama L [17]

Answer:

a) P(Y > 76) = 0.0122

b) i) P(both of them will be more than 76 inches tall) = 0.00015

   ii) P(Y > 76) = 0.0007

Step-by-step explanation:

Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.

To find - (a) If a man is chosen at random from the population, find

                    the probability that he will be more than 76 inches tall.

              (b) If two men are chosen at random from the population, find

                    the probability that

                    (i) both of them will be more than 76 inches tall;

                    (ii) their mean height will be more than 76 inches.

Proof -

a)

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{S.D}) > \frac{( 76- mean)}{S.D})

                 = P(Z >  \frac{( 76- mean)}{S.D})

                 = P(Z > \frac{76 - 69.7}{2.8})

                 = P(Z > 2.25)

                 = 1 - P(Z  ≤ 2.25)

                 = 0.0122

⇒P(Y > 76) = 0.0122

b)

(i)

P(both of them will be more than 76 inches tall) = (0.0122)²

                                                                           = 0.00015

⇒P(both of them will be more than 76 inches tall) = 0.00015

(ii)

Given that,

Mean = 69.7,

\frac{S.D}{\sqrt{N} } = 1.979899,

Now,

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{\frac{S.D}{\sqrt{N} } })) > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- 69.7)}{1.979899 }))

                 = P(Z > 3.182)

                 = 1 - P(Z ≤ 3.182)

                 = 0.0007

⇒P(Y > 76) = 0.0007

6 0
3 years ago
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