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2 years ago

Roció hará un circulo con un diámetro de 22.8 cm cuánto medirá un radio

Mathematics

1 answer:

Kruka [31]2 years ago

7 0

Answer:

r = 11.4 cm

Step-by-step explanation:

The question says that, "Spray will make a circle with a diameter of 22.8 cm how long a radius will measure."

Given that,

The diameter of the circle, d = 22.8 cm

We know that the relation between the diameter and the circle is given by :

d = 2r

Where

r is the radius of the circle

r = d/2

r = 22.8/2

r = 11.4 cm

So, the radius of the circle is equal to 11.4 cm.

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Evaluate the expression 8x when x=2.

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2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=7%20-%209w%20%3D%20%20-%2029%20" id="TexFormula1" title="7 - 9w = - 29 " alt="7 - 9w = - 29

Oksana_A [137]

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2 years ago

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The weights of 67 randomly selected axles were found to have a variance of 3.85. Construct the 80% confidence interval for the p

VLD [36.1K]

Answer:

$3.13$

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

Variance = 3.85

We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

$\chi^2_{1-\frac{\alpha}{2}}= 51.770$

Chi square critical value for upper tail =

$\chi^2_{\frac{\alpha}{2}}= 81.085$

80% confidence interval:

$\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}$

Putting values, we get,

$=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13$

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

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2 years ago