Answer:
class assignment seems to discriminate against Art Club members
Step-by-step explanation:
The probability of getting the requested assignment given that the student was in Art Club was ...
P(got class | art club) = P(got class & art club)/P(art club)
P(got class | art club) = (100/500)/(165/500) ≈ 60.6%
__
P(got class | not club) = P(got class & not club)/P(not club)
P(got class | not club) = (265/500)/(335/500) ≈ 79.1%
It looks like George's theory may be incorrect, as a significantly greater percentage of non-club students got their requested class than did club students. The class assignment process and art club membership are not independent, suggesting an unfair disadvantage for club students.
Answer:
u probably need to just count the boxes. some are half so take it as 0.5
let the size of each box be 1 cm.
1) 14 cm or 14 unit (i m sure for this one)
2) it would approximately be 15 unit
my teacher taught me if the boxes are have different measurement other than half so just don't count that
u will fine your answers at the back of your textbook
Answer:
uhhh idek
Step-by-step explanation:
Answer: ![90\ in^2](https://tex.z-dn.net/?f=90%5C%20in%5E2)
Step-by-step explanation:
The missing figure is attached.
Direct variation equations have the following form:
![y=kx](https://tex.z-dn.net/?f=y%3Dkx)
Where "k" is the Constant of variation.
Since the width of the rectangle varies directly as its length, you can write this equation:
![w=kl](https://tex.z-dn.net/?f=w%3Dkl)
Where "l" is the lenght in inches and "w" is the width in inches of the rectangle.
Observe in the figure that when
; then you can substitute them into the equation and solve for "k":
Therefore, the width is:
![w=(0.4)(15\ in)\\\\w=6\ in](https://tex.z-dn.net/?f=w%3D%280.4%29%2815%5C%20in%29%5C%5C%5C%5Cw%3D6%5C%20in)
Since the area of the rectangle can be calculated multiplying its lenght by its width, you get that the area of the rectangle that is 15 inches long is:
![A=(15\ in)(6\ in)\\\\A=90\ in^2](https://tex.z-dn.net/?f=A%3D%2815%5C%20in%29%286%5C%20in%29%5C%5C%5C%5CA%3D90%5C%20in%5E2)
The correct answers are:
a) difference in T between Rome and Oslo: 9 °C (11- 2=9)
b) T in Kiev at 6pm: 7 °C (1+6=7)