C is the answer.............
Answer:
The amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600
Step-by-step explanation:
Let x be the amount in the account at 12% interest
So, 6000-x is the amount in the second account at 7% interest

First account:
Second account : 
We are given that At the end of the first year he had earned $590 in interest.
So, 
So,the amount in the account at 12% interest is $3400
The amount in the second account at 7% interest =6000-x=6000-3400=2600
Hence the amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600
Answer:
<h2><u><em>
2-x</em></u></h2>
Step-by-step explanation:
(14 - 7x)/7 =
[7(2-x)]/7 =
2-x
1/2 x 3/4
1 x 3 / 2 x 4
= 3/8