I think the answer would be D
Answer:
The new width = 2 inches
Step-by-step explanation:
Original dimensions of the rectangular photo:
Length : width = 8 inches : 4 inches
Reduced dimensions of the rectangular photo:
Let
x = the new width
Length : width = 4 inches : x inches
Equate both dimensions to get the value of x
Length : width
8 inches : 4 inches = 4 inches : x inches
8 / 4 = 4 / x
Cross product
8 * x = 4 * 4
8x = 16
x = 16/8
x = 2 inches
The new width = 2 inches
Step-by-step explanation:
The Taylor series expansion is:
Tₙ(x) = ∑ f⁽ⁿ⁾(a) (x − a)ⁿ / n!
f(x) = 1/x, a = 4, and n = 3.
First, find the derivatives.
f⁽⁰⁾(4) = 1/4
f⁽¹⁾(4) = -1/(4)² = -1/16
f⁽²⁾(4) = 2/(4)³ = 1/32
f⁽³⁾(4) = -6/(4)⁴ = -3/128
Therefore:
T₃(x) = 1/4 (x − 4)⁰ / 0! − 1/16 (x − 4)¹ / 1! + 1/32 (x − 4)² / 2! − 3/128 (x − 4)³ / 3!
T₃(x) = 1/4 − 1/16 (x − 4) + 1/64 (x − 4)² − 1/256 (x − 4)³
f(x) = 1/x has a vertical asymptote at x=0 and a horizontal asymptote at y=0. So we can eliminate the top left option. That leaves the other three options, where f(x) is the blue line.
Now we have to determine which green line is T₃(x). The simplest way is to notice that f(x) and T₃(x) intersect at x=4 (which makes sense, since T₃(x) is the Taylor series centered at x=4).
The bottom right graph is the only correct option.
We have a square garden of 400 square foot.
The area of a square is:

where x: side length.
In this case:
![\begin{gathered} A=400=x^2 \\ x=\sqrt[]{400}=20\text{ ft} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20A%3D400%3Dx%5E2%20%5C%5C%20x%3D%5Csqrt%5B%5D%7B400%7D%3D20%5Ctext%7B%20ft%7D%20%5Cend%7Bgathered%7D)
The perimeter of the square is the sum of the lengths of the sides of the square. As they are all equal, we can write:

The fencing is priced at $1.50 per foot. If we add the 7% sales tax to this price we get:

The fencing will be installed in all the perimeter (80 ft).
We can calculate the total cost by multiplying the sales price ($1.605 per foot) and the perimeter (80 ft):

Answer: the fencing will cost a total of $128.40
Are you asking if it's true or false?
Because it's false, they are not necessarily adjacent.