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Ket [755]
2 years ago
7

What is the ratio of rolling a 2 to rolling a 5?

Mathematics
2 answers:
joja [24]2 years ago
8 0
1:6
1/6 or 0.1667 chance

Given a 6-sided dice, the probability for rolling a 2 and a 5 would be the same. You have a 1 in 6 chance of rolling either. 1 : 6
soldi70 [24.7K]2 years ago
7 0

Answer:

when we have two dice, the odds are not as simple. For example, there's only one way to roll a two (snake eyes), but there's a lot of ways to roll a seven (1+6, 2+5, 3+4).

Step-by-step explanation:

got em

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If f(x) = x-6 and g(x)= 1/2x (x+3), find g(x) * f(x)
sertanlavr [38]

Answer:

Final answer is g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}.

Step-by-step explanation:

given functions are f(x)=x-6 and g\left(x\right)=\frac{1}{2x\left(x+3\right)}.

Now we need to find about what is the value of g\left(x\right)*f\left(x\right).

g\left(x\right)*f\left(x\right) simply means we need to multiply the value of  f(x)=x-6 and g\left(x\right)=\frac{1}{2x\left(x+3\right)}.

g\left(x\right)\cdot f\left(x\right)=\frac{1}{2x\left(x+3\right)}\cdot\left(x-6\right)

g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}

Hence final answer is g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}.

5 0
3 years ago
If the common difference in an article is -3 and the first term is 7 what is the 14th term?
Wittaler [7]
I got A, -32, but it has been awhile since I have learned this in my math class. You might want to wait for someone else to verify this answer. 
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n= -3.1

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