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Marizza181 [45]
3 years ago
15

A polynomial expression is shown below.

Mathematics
1 answer:
Kaylis [27]3 years ago
4 0

Answer: m = -3

Step-by-step explanation:

The polynomial expression

(mx+8)(2x−4)

The next step is to expand the bracket

(mx × 2x) + (mx × -4) + (8×2x) + (8× -4)

2mx^2 - 4mx + 16x -32

2mx^2 - 4mx + 16x -32

2mx^2 + 12x -32 - - - - - - - - - - 1

From the question,

The expression is simplified to

−6x2+28x−32 - - - - - - - - - - - - 2

This means equation 1 = equation 2

Comparing both equations, we have

2mx^2 = −6x^2

2m = -6

m = -6/2 = -3

The correct option is a

The expression becomes

(-3x+8)(2x−4)

Let us check

Expanding the brackets,

(-3x × 2x) + (-3x ×-4)+ (8×2x) + (8×-4)

= -6x^2 +12x + 16x - 32

= -6x^2 +18x - 32

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If ab= 7x-6 and bc= 12-2x. Then what does ac equal?
ra1l [238]
Ab = (7x-6) →   b = (7x-6)/a   (1)

bc = (12-2x) → b = (12-2x)/c   (2)

Since (1) = (2) → (7x-6)/a = (12-2x)/c OR  a/c = (7x-6)/(12-2x)  (3)

Multiply  both numerators of (3) by the SQUARE of their  respective denominators;

(a*c²)/c = (7x-6)(12-2x)²/(12-2x)
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3 years ago
A triangle has the following measurements: B=79 degrees a=5ft
11Alexandr11 [23.1K]
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Given: Tangents LA and LB, m∠AOB=110°. Find: m∠ALO.
Yuri [45]

Answer:

The measure of angle ALO = 35°

Step-by-step explanation:

* Lets talk about the tangents to a circle drawn from a point

 outside the circle:

- They are equal in length

- They are perpendicular to the radii at the point of tang-ency

- If we join the points of tang-ency withe the center of the circle

 and join the outside point with center of the circle, we

 formed two congruent triangles

* Now lets check our problem

- AL and LB are two tangents to the circle O ant points A and B

∴ LA = LB ⇒ (1)

- OA and OB are radii in circle O

∴ OA = OB ⇒ (2)

∴ OA ⊥ AL and OB ⊥ BL ⇒ radius and tangent

∴ m∠OAL = 90° , m∠OBL = 90

∴ m∠OAL = m∠OBL ⇒ (3)

* From (1) , (2) , (3)

- The two triangles LAO and LBO are congruent ⇒ SAS

- SAS is one case of congruence

∵ The lengths of two sides and the measure of the including

  angle between them in one triangle equal to the

  corresponding sides and angles in the second triangle,

  then the two triangles are congruent

∴ m∠LOA = m∠LOB

∵ m∠AOB = 110°

∴ m∠LOA = m∠LOB = 110/2 = 55°

* In ΔLAO

∵ m∠ LAO = 90° , m∠LOA = 55°

∴ m∠ALO = 180 - (90 + 55) = 180 - 145 = 35°

* The measure of angle ALO = 35°

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Pouring a glass of milk is it discrete or continuous on a graph
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I think it would be continuous.
5 0
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