The intersection of lines y=-14x+3 and y=-32x+3 is (0, 3)
<h3>How to determine the intersection of the lines?</h3>
The lines are given as:
y = -14x + 3 and y = -32x+3
Substitute y = -32x+3 in
-32x+3 = -14x + 3
Evaluate the like terms
-18x = 0
Divide by -18
x = 0
Substitute x = 0 in y = -14x + 3
y = -14(0) + 3
Evaluate
y = 3
Hence, the intersection of lines y=-14x+3 and y=-32x+3 is (0, 3)
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Hi there!
So if BC and DA are the same, then BA and CD are also the same...
The only one that’s left is BD.
Therefore, the shortest side is BD.
It’s 22/3 I think so that’s the answer
40.25 you add everything together then multiply by .6
M=(6-1)/(8-5)=5/3
y=5x/3+b, using (5,1)
1=25/3+b
b=-22/3
y=(5x-22)/3
...
m=(8-3)/(-1--4)=5/3...
y=5x/3+b, using (-1,8)
8=-5/3+b
b=29/3
y=(5x+29)/3
Since they have the same slope and difference y-intercepts they are parallel lines and will never intersect.
