Answer:
All of the above
Step-by-step explanation:
dy/dt = y/3 (18 − y)
0 = y/3 (18 − y)
y = 0 or 18
d²y/dt² = y/3 (-dy/dt) + (1/3 dy/dt) (18 − y)
d²y/dt² = dy/dt (-y/3 + 6 − y/3)
d²y/dt² = dy/dt (6 − 2y/3)
d²y/dt² = y/3 (18 − y) (6 − 2y/3)
0 = y/3 (18 − y) (6 − 2y/3)
y = 0, 9, 18
y" = 0 at y = 9 and changes signs from + to -, so y' is a maximum at y = 9.
y' and y" = 0 at y = 0 and y = 18, so those are both asymptotes / limiting values.
This deal is cheap! Well, the answer is 60 cents. To get these problems, divide 10.80 by 18, which is equal to 1.5 a dozen.
Answer:
Oliver completed his training work in 50.25 hours
Step-by-step explanation:
we know that
1 day= 24 hours
1 hour=60 minutes
we have
2 days, 2 h, and 15 min
<u><em>Convert days to hours</em></u>
2 days=2(24)=48 hours
<u><em>Convert minutes to hour</em></u>
15 min=15(1/60)=1/4=0.25 h
so
2 days, 2 h, and 15 min=(48)+(2)+(0.25)=50.25 h
therefore
Oliver completed his training work in 50.25 hours
Answer:
Step-by-step explanation:
Area of triangle = 0.5 × Base × Height
→ Substitute in the values
200 = 0.5 × 5x × 5x
→ Simplify
200 = 12.5x²
→ Divide both sides by 12.5
16 = x²
→ Square root both sides
4 = x ∴ x = 4
