<u>Explanation</u>:
It is an all-too-often used technology today in connecting several computers together via a network.
Routing simple terms means the action of selecting the path taken by the traffic of data in a network of computers. The routing systems involve the use of both wireless and cable based architectures. Some common example of routing systems includes:
- Dynamic Routing
- Static routing
- Default Routing
Answer:
#include <iostream>
#include<iomanip>
using namespace std;
double DrivingCost(double drivenMiles, double milesPerGallon, double dollarsPerGallon)
{
double dollarCost = 0;
dollarCost = (dollarsPerGallon * drivenMiles) / milesPerGallon;
return dollarCost;
}
int main()
{
double miles = 0;
double dollars = 0;
cout << "Enter miles per Gallon : ";
cin >> miles;
cout << "Enter dollars per Gallon: ";
cin >> dollars;
cout << fixed << setprecision(2);
cout << endl;
cout << "Gas cost for 10 miles : " << DrivingCost(10, miles, dollars) << endl;
cout << "Gas cost for 50 miles : " <<DrivingCost(50, miles, dollars) << endl;
cout << "Gas cost for 400 miles: "<<DrivingCost(400, miles, dollars) << endl;
return 0;
}
Explanation:
- Create a method definition of DrivingCost that accepts three input double data type parameters drivenMiles, milesPerGallon, and dollarsPerGallon and returns the dollar cost to drive those miles
.
- Calculate total dollar cost and store in the variable, dollarCost
.
- Prompt and read the miles and dollars per gallon as input from the user
.
- Call the DrivingCost function three times for the output to the gas cost for 10 miles, 50 miles, and 400 miles.
Answer:
A: Create the product that customers
Explanation:
I did it on edgy
Answer:
This is not what this platform is supposed to be used for
Explanation:
Fortnite isnt a real game lol get a life
Answer:
Explanation:
The system will be deadlock free if the below two conditions holds :
Proof below:
Suppose N = Summation of all Need(i), A = Addition of all Allocation(i), M = Addition of all Max(i). Use contradiction to prove.
Suppose this system isn't deadlock free. If a deadlock state exists, then A = m due to the fact that there's only one kind of resource and resources can be requested and released only one at a time.
Condition B, N + A equals M < m + n. Equals N + m < m + n. And we get N < n. It means that at least one process i that Need(i) = 0.
Condition A, Pi can let out at least 1 resource. So there will be n-1 processes sharing m resources now, Condition a and b still hold. In respect to the argument, No process will wait forever or permanently, so there's no deadlock.
