Answer:
The answer is below
Explanation:
Given that:
Frame transmission time (X) = 40 ms
Requests = 50 requests/sec, Therefore the arrival rate for frame (G) = 50 request * 40 ms = 2 request
a) Probability that there is success on the first attempt = 
but k = 0, therefore Probability that there is success on the first attempt = 
b) probability of exactly k collisions and then a success = P(collisions in k attempts) × P(success in k+1 attempt)
P(collisions in k attempts) = [1-Probability that there is success on the first attempt]^k = ![[1-e^{-G}]^k=[1-0.135]^k=0.865^k](https://tex.z-dn.net/?f=%5B1-e%5E%7B-G%7D%5D%5Ek%3D%5B1-0.135%5D%5Ek%3D0.865%5Ek)
P(success in k+1 attempt) =
Probability of exactly k collisions and then a success = 
c) Expected number of transmission attempts needed = probability of success in k transmission = 
Answer:
C is the correct answer to your question
<span>The correct answer is Intranet chat rooms</span>
The loop terminates when "xxxxx" is read in. If the word is land, the string followed by "land" get outputted. The same with air, and water.
Explanation:
int land = 0;
int air = 0;
int water = 0;
String word = "";
while(!(word.equals("xxxxx"))) {
word = stdin.next();
if(word.equals("land")) {
land++;
}else if(word.equals("air")) {
air++;
}else if(word.equals("water")) {
water++;
}
}
System.out.println("land:" + land);
System.out.println("air:" + air);
System.out.println("water:" + water);
Answer:
SAN
Explanation:
A Storage Area Network (SAN) is a high-speed sub network of shared storage devices. A SAN's architecture works in a way that makes all storage devices available to all servers on a LAN or WAN. As more storage devices are added to a SAN, they too will be accessible from any server in the larger network.
