Answer:
When a programmer tries to access an item in an array cell whose index is greater than or equal to the array's logical size, this data element or item is garbage. This means that currently, the item is not the part of the program's useful data. Garbage contains objects or data which will not be used by a program running on it. So the value returned could be either of the two:
- Value would be an arbitrary or random number if it is an array of numbers. Arbitrary means that the value is not predefined or specified in advance.
- Value returned would be null if it is an array of objects.
<span>Not a valid IPv6 address
A valid IPv6 address consist of 8 groups of 4 hexadecimal numbers separated by colons ":". But that can make for a rather long address of 39 characters. So you're allowed to abbreviate an IPv6 address by getting rid of superfluous zeros. The superfluous zeros are leading zeros in each group of 4 digits, but you have to leave at least one digit in each group. The final elimination of 1 or more groups of all zeros is to use a double colon "::" to replace one or more groups of all zeros. But you can only do that once. Otherwise, it results in an ambiguous IP address. For the example of 2001:1d5::30a::1, there are two such omissions, meaning that the address can be any of
2001:1d5:0:30a:0:0:0:1
2001:1d5:0:0:30a:0:0:1
2001:1d5:0:0:0:30a:0:1
And since you can't determine which it is, it's not a valid IP address.</span>
<span>C. Get the help of someone with specialized knowledge in the area.</span>
Answer:
The correct answer for the given question is Integer.parseInt( string variable );
Explanation:
Integer.parseInt( string variable ); is the method in a java programming language that convert the string into the integer value. It takes a string variable and converted into the integer.
Following are the program in java which convert the string value into an integer value.
class Main
{
public static void main(String []args) // main function
{
String str1 = "10009";
// variable declaration
int k = Integer.parseInt(str1);
// convert the string into integer.
System.out.println("Converted into Int:" + k);
}
}
Output:
Converted into Int:10009
Convert.toInt( stringVariable );
Convert.parseInt( stringVariable,Integer.toInt( stringVariable ); are not any method to convert the string into integer .
Therefore the correct answer is :Integer.parseInt( stringVariable );
Answer:
The first one
Explanation:
The other ones don’t make sense
